Spring Aop 用xml的方式实现

x33g5p2x  于2021-03-14 发布在 Spring  
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学习完了Spring AOPAnnotation之后在再学xml方式的我觉得就很简明易懂了。这个案例不再将一些细节性的问题再次叙述,请看案例代码,如下所示:

1、 编写被代理对象:

import org.springframework.stereotype.Component;
import com.spring.dao.UserDao;

@Component("userService")
public class UserServiceImpl implements UserService{
	private UserDao userDao;
	
	public void setUserDao(UserDao userDao) {
		this.userDao = userDao;
	}
	
	//在下面方法前面加逻辑
	public void HelloWorld(){
		System.out.println("helloworld");
	}
}

2、编写配置文件:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:aop="http://www.springframework.org/schema/aop"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
           http://www.springframework.org/schema/context
           http://www.springframework.org/schema/context/spring-context-2.5.xsd
           http://www.springframework.org/schema/aop
           http://www.springframework.org/schema/aop/spring-aop-2.5.xsd" >
    <context:annotation-config/>
    <!-- 配置容器资源扫描的包 -->
   <context:component-scan base-package="com.spring" />
 	<!-- 将前面类写入容器 -->
 	<bean id="logInterceptor" class="com.spring.aop.LogInterceptor" />
 	<!-- 配置AOP -->
 	<aop:config>
 		<!-- 声明pointcut -->
 		<aop:pointcut expression="execution(public * com.spring.service..*.*(..))" id="servicepoint" />
 		<!-- 声明切面类 -->
 		<aop:aspect id="aspectLog" ref="logInterceptor">
 			<aop:before method="BeforeMethod" pointcut-ref="servicepoint"/>
 			<aop:after-returning method="AfterMethod" pointcut-ref="servicepoint"/>
 			<aop:around method="aroundProcced" pointcut-ref="servicepoint"/>
 		</aop:aspect>
 	</aop:config>
</beans>

3、编写测试文件:

package com.spring.test;

import org.junit.Test;
import org.springframework.beans.factory.BeanFactory;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import com.spring.service.UserService;

public class SpringTest {
	@Test
	public void test01() {
		BeanFactory applicationContext = new ClassPathXmlApplicationContext(
				"beans.xml");
		UserService user = (UserService) applicationContext.getBean("userService");
		user.HelloWorld();
	}
}

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