1.小乐乐与字符串
2.KiKi去重整数并排序
方法一:
方法二:
35.KiKi学结构体和指针
#include<stdio.h>
int main()
{
char arr[8000] = {0};
scanf("%s",arr);
long c = 0;
long ch = 0;
long chn = 0;
char *p = arr;
while(*p!='\0')
{
if(*p=='C')
{
c++;
}
else if(*p=='H')
{
ch+=c;
}
else if(*p=='N')
{
chn+=ch;
}
p++;
}
printf("%lld",chn);
return 0;
}
#include<stdio.h>
int main()
{
int n = 0;
int arr[1001] = {0};
int tmp = 0;
scanf("%d",&n);
for(int i = 0;i<n;i++)
{
scanf("%d",&tmp);
arr[tmp] = tmp;
}
for(int i = 0;i<1001;i++)
{
if(arr[i]!=0)
{
printf("%d ",arr[i]);
}
}
return 0;
}
#include<stdio.h>
void bubble_sort(int arr[], int n)
{
for (int i = 0; i < n - 1; i++)
{
for (int j = 0; j < n - i - 1; j++)
{
if (arr[j] > arr[j + 1])
{
int temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
}
}
int main()
{
int arr[1000] = { 0 };
int n = 0;
scanf("%d", &n);
int i = 0;
for (i = 0; i < n; i++)
{
scanf("%d", &arr[i]);
}
bubble_sort(arr, n);
for (i = 0; i < n - 1; i++)
{
if (arr[i] == arr[i + 1])
{
int k = 0;
for (k = i; k < n - 1; k++)
{
arr[k] = arr[k + 1];
}
n--;
i--;
}
}
for (i = 0; i < n; i++)
{
printf("%d ", arr[i]);
}
return 0;
}
#include<stdio.h>
#include<malloc.h>
struct Node
{
int num;
struct Node* next;
};
int main()
{
int n = 0;
scanf("%d",&n);
int i = 0;
int m = 0;
int d = 0;//要删除的元素
struct Node* list = NULL;//指向链表的指针
struct Node* tail=NULL;//指向链表尾部元素的指针
for(i = 0;i<n;i++)
{
scanf("%d",&m);
struct Node*pn = (struct Node*)malloc(sizeof(struct Node));
pn->num = m;
pn->next = NULL;
if(list==NULL)
{
list = pn;
tail = pn;
}
else
{
tail->next = pn;
tail = pn;
}
}
//接收要删除的元素
scanf("%d",&d);
//删除列表中指定的元素
struct Node* cur = list;
struct Node* prev = NULL;
while(cur)
{
if(cur->num==d)
{
//删除
struct Node*pd = cur;
if(cur==list)
{
list = list->next;
cur = list;
}
else
{
prev->next = cur->next;
cur = prev->next;
}
free(pd);
n--;
}
else
{
prev = cur;
cur = cur->next;
}
}
//
printf("%d\n",n);
cur = list;
while(cur)
{
printf("%d ",cur->num);
cur = cur->next;
}
//释放单链表
cur = list;
struct Node*del = NULL;
while(cur)
{
del = cur;
cur = cur->next;
free(del);
}
list = NULL;
return 0;
}
版权说明 : 本文为转载文章, 版权归原作者所有 版权申明
原文链接 : https://blog.csdn.net/m0_57304511/article/details/122971010
内容来源于网络,如有侵权,请联系作者删除!