html表单只使用jquery发布第一个数据

4sup72z8  于 2021-06-20  发布在  Mysql
关注(0)|答案(0)|浏览(177)
<?php
    for ($i = 1; $i <= 5; $i++) {
        $name = 'name' . $i;
        $id = 'id' . $i;
        echo '<form method="POST" action="" name = "' . $name . '" id = "' . $id . '">';
        echo'<input type="number" name="roll" id="roll" placeholder="Enter Roll"><br>' .
        '<input type="text" name="name" id="name" placeholder="Enter Name"><br>' .
        '<input type="text" name="address" id="address" placeholder="Enter Address"><br>' .
        '<button type="button" onclick="submitdata(this);"> Submit </button><br>';
        echo '</form><br>';
    }
?>

这是php代码。我在php echo标记中插入表单。我使用mysql数据库。

function submitdata() {
    var roll = document.getElementById("roll").value;
    var name = document.getElementById("name").value;
    var address = document.getElementById("address").value;
    // Returns successful data submission message when the entered information is stored in database.
    var dataString = 'roll=' + roll + '&name=' + name + '&address=' + address;
    if (roll == '' || name == '' || address == '') {
        alert("Please Fill All Fields");
    } else {
        // AJAX code to submit form.
        $.ajax({
            type: "POST",
            url: "submit.php",
            data: dataString,
            cache: false,
            success: function (html) {
                alert(html);
            }
        });
    }
    return false;
}

这是我的javascript代码。请帮我提个建议。如何从php循环插入表单数据?

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