在日期范围之间生成日期

2mbi3lxu  于 2021-07-24  发布在  Java
关注(0)|答案(11)|浏览(287)

我需要填充一个表来存储两个给定日期之间的日期范围：09/01/11-10/10/11
因此，在本例中，表将从2011年1月9日开始每天存储，直到2011年10月10日，我想知道在sql server中是否有一种巧妙的方法来实现这一点—我目前正在使用sql server 2008。谢谢

sqlsql-servertsqlrangesql-server-2008

11条答案

按热度按时间
qcuzuvrc

qcuzuvrc1#

易用sql 2005+；如果你有一个数字或计数表就容易了。我在下面伪造了它：

DECLARE @StartDate DATE = '20110901'
  , @EndDate DATE = '20111001'

SELECT  DATEADD(DAY, nbr - 1, @StartDate)
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS Nbr
          FROM      sys.columns c
        ) nbrs
WHERE   nbr - 1 <= DATEDIFF(DAY, @StartDate, @EndDate)

如果您有一个tally表，请用该表替换子查询。没有递归。

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vfh0ocws

vfh0ocws2#

如果您使用的是sql server 2005或更新版本，请尝试以下操作：

WITH Dates AS (
        SELECT
         [Date] = CONVERT(DATETIME,'09/01/2011')
        UNION ALL SELECT
         [Date] = DATEADD(DAY, 1, [Date])
        FROM
         Dates
        WHERE
         Date < '10/10/2011'
) SELECT
 [Date]
FROM
 Dates
 OPTION (MAXRECURSION 45)

一个很好的例子酷的东西，你可以做一个cte。

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disbfnqx

disbfnqx3#

--声明

DECLARE @dates TABLE(dt datetime)    
DECLARE @dateFrom datetime
DECLARE @dateTo datetime

SET @dateFrom = '2001/01/01'
SET @dateTo = '2001/01/12'

--查询：

WHILE(@dateFrom < @dateTo)
BEGIN
   SELECT @dateFrom = DATEADD(day, 1,@dateFrom)
   INSERT INTO @dates 
   SELECT @dateFrom
END

--输出

SELECT * FROM @dates
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xqnpmsa8

xqnpmsa84#

这是一个不需要递归的解决方案，同时，这个表值函数可以在许多查询中重用，而无需再次重复样板变量的声明。对于那些不希望递归的人来说，这是唯一的选择。
创建以下简单函数：

CREATE FUNCTION [dbo].[GenerateDateRange]
(@StartDate AS DATE,
 @EndDate AS   DATE,
 @Interval AS  INT
)
RETURNS @Dates TABLE(DateValue DATE)
AS
BEGIN
    DECLARE @CUR_DATE DATE
    SET @CUR_DATE = @StartDate
    WHILE @CUR_DATE <= @EndDate BEGIN
        INSERT INTO @Dates VALUES(@CUR_DATE)
        SET @CUR_DATE = DATEADD(DAY, @Interval, @CUR_DATE)
    END
    RETURN;
END;

然后选择：

select *
from dbo.GenerateDateRange('2017-01-03', '2017-12-01', 1)
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lnlaulya

lnlaulya5#

我知道这是一个旧的线程，但我不得不承认我的沮丧，在这里给出的递归和循环解决方案过多。我想知道有多少人意识到递归只不过是一个非常昂贵的循环？我理解创建表值函数的愿望，但我建议以下方法更有效，因为它是基于集合的，没有循环、递归或重复的单insert语句：

CREATE FUNCTION dbo.GenerateDateRange(@StartDate AS DATE, @EndDate AS DATE)
RETURNS TABLE WITH SCHEMABINDING AS
    WITH e1(n) AS (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) AS x(n)) -- 16 records
        ,e2(n) AS (SELECT 1 FROM e1 a CROSS JOIN e1 b) -- 16^2 or 256 records (16*16)
        ,cteTally(n) AS (SELECT ROW_NUMBER() over (ORDER BY 1) AS n FROM e2 a CROSS JOIN e2 b) -- 16^4 or 65,536 records (256*256)
    SELECT DATEADD(DAY, n-1, @StartDate)
    FROM cteTally
    WHERE n <= DATEDIFF(DAY, @StartDate, @EndDate) + 1;
GO
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7uzetpgm

7uzetpgm6#

使用mvj的f_table_date函数，它非常棒：
http://www.sqlteam.com/forums/topic.asp?topic_id=61519
一旦你实现了这一点，只需传入开始和结束日期，你就可以插入所有的日期之间。

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w8rqjzmb

w8rqjzmb7#

使用@abe miesler的答案，为了其他人的方便，我将它构建到一个tvf中，用于sqlserver2008以后的版本。它可能会帮助其他人-我必须找到一种方法，包括在tvf的cte！

--Generate a range of dates with interval option, courtesy of Abe Miessler for the core query here!
ALTER FUNCTION [dbo].[DateRange]
(@startDate AS DATE,
 @EndDate AS   DATE,
 @interval AS  INT
)
RETURNS @Dates TABLE(dateValue DATE)
AS
     BEGIN
         WITH Dates
              AS (
              SELECT [Date] = CONVERT( DATETIME, @startDate)
              UNION ALL
              SELECT [Date] = DATEADD(DAY, ISNULL(@interval, 1), [Date])
              FROM Dates
              WHERE Date < @EndDate)
              INSERT INTO @Dates
                     SELECT [Date]
                     FROM Dates
                     OPTION(MAXRECURSION 900);
         RETURN;
     END;
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b09cbbtk

b09cbbtk8#

这是一个旧的线程，但如果它对任何人都有帮助，这就是我在支持cte的sqlserver的现代版本中使用的。这还提供了一周中的某一天，可以对其进行调整，以提供可能需要的其他值（即季度、月份等）。

DECLARE @StartDate datetime
DECLARE @EndDate datetime
SET @StartDate = '1/1/2020'
SET @EndDate = '12/31/2020'
DECLARE @DayTable Table(theDate date, theDayOfWeek nvarchar(50));
WITH DayTable AS (SELECT CAST(@StartDate AS DATETIME) theDate, DATENAME(dw, @StartDate) theDayOfWeek UNION ALL SELECT DATEADD(dd, 1, theDate), DATENAME(dw,DATEADD(dd, 1, theDate)) FROM DayTable s  WHERE DATEADD(dd, 1, theDate) <= CAST(@EndDate AS DATETIME)) 
INSERT INTO @DayTable(theDate, theDayOfWeek) SELECT theDate, theDayOfWeek FROM DayTable OPTION (MAXRECURSION 365); 
SELECT * FROM @DayTable
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ybzsozfc

ybzsozfc9#

Declare @StartDate datetime = '2015-01-01'
Declare @EndDate datetime = '2016-12-01'
declare @DaysInMonth int
declare @tempDateRange Table
(
DateFrom datetime,
DateThru datetime
);

While @StartDate<=@EndDate
begin
    SET @DaysInMonth=DAY(DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,-1,@StartDate),0)))

    IF DAY(@StartDate)=1 
        SET @EndDate=DATEADD(DAY,14,@StartDate)
    ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=30
        SET @EndDate=DATEADD(DAY,14,@StartDate)
    ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=31
        SET @EndDate=DATEADD(DAY,15,@StartDate)
    ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=28
        SET @EndDate=DATEADD(DAY,12,@StartDate)
    ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=29
        SET @EndDate=DATEADD(DAY,13,@StartDate)

    INSERT INTO @tempDateRange (DateFrom,DateThru)
    VALUES 
     (
        @StartDate,
        @EndDate
     )

    SET @StartDate=DATEADD(DAY,1,@EndDate)

    IF @EndDate< '2016-12-31'
     IF DAY(@StartDate)=1 
        SET @EndDate=DATEADD(DAY,14,@StartDate)
     ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=30
        SET @EndDate=DATEADD(DAY,14,@StartDate)
     ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=31
        SET @EndDate=DATEADD(DAY,15,@StartDate)
     ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=28
        SET @EndDate=DATEADD(DAY,12,@StartDate)
     ELSE IF DAY(@StartDate)=16 AND @DaysInMonth=29
        SET @EndDate=DATEADD(DAY,13,@StartDate)
end ;

select * from @tempDateRange

+++++++++++++++++++++++++++++
Result:
DateFrom |DateThru
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bz4sfanl

bz4sfanl10#

如果因为某种原因你不能 declare 变量，例如在looker中使用派生表时，可以如下所示：

select
  dateadd(day, nbr - 1, convert(date, '2017-01-01')) as d
from (
  select row_number() over (order by c.object_id) as nbr from sys.columns c
) nbrs
where
  nbr - 1 <= datediff(
    day,
    convert(date, '2017-01-01'),
    convert(date, '2018-12-31')
  )

顺便说一句，在lookerml中，日期序列视图可能是这样的：

view: date_series {
  derived_table: {
    sql:
      select
        dateadd(day, nbr - 1, convert(date, '2017-01-01')) as d
      from (
        select row_number() over (order by c.object_id) as nbr from sys.columns c
      ) nbrs
      where
        nbr - 1 <= datediff(day, convert(date, '2017-01-01'), convert(date, '2018-12-31')) ;;
  }

  dimension: date {
    primary_key: yes
    type: date
    sql: ${TABLE}.d ;;
  }
}
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arknldoa

arknldoa11#

CREATE table #ProductSales (ProjectID Int, ProjectName varchar(100), TotalBillableFees Money, StartDate Date, EndDate Date, DataDate Date)

  Insert into #ProductSales
  Values
  (373104,'Product Sales - Flex Creation Test',40000.00,'2019-04-01','2020-06-01','2019-08-01'),
  (375111,'Product Sales - SMART',40000.00,'2019-04-01','2019-09-01','2019-08-01')

  ;WITH Dates AS (
        SELECT ProjectiD
        ,Convert(decimal(10,2),TotalBillableFees/IIF(DATEDIFF(MONTH,StartDate,EndDate)=0,1,DATEDIFF(MONTH,StartDate,EndDate))) AS BillableFeesPerMonths,EndDate
         ,[Date] = CONVERT(DATETIME,EOMONTH(StartDate))
         FROM #ProductSales
        UNION ALL SELECT ProjectiD,BillableFeesPerMonths,EndDate,
         [Date] = DATEADD(MONTH, 1, [Date])
        FROM
         Dates
        WHERE
         Date < EOMONTH(EndDate)
) SELECT ProjectID,BillableFeesPerMonths,
 CAST([Date] as Date) Date
FROM
 Dates
 OPTION (MAXRECURSION 45)
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