incubator-doris multi sum distianct need return null, not zero

r6l8ljro  于 2022-04-22  发布在  Java
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mysql> select sum(distinct id), sum(distinct int_col) from alltypesagg;
+--------------------+-------------------------+
| sum(DISTINCT id) | sum(DISTINCT int_col) |
+--------------------+-------------------------+
| 0 | 0 |
+--------------------+-------------------------+
1 row in set (0.01 sec)

mysql> select sum(distinct id) from alltypesagg;
+--------------------+
| sum(DISTINCT id) |
+--------------------+
| NULL |
+--------------------+
1 row in set (0.01 sec)

当表中没有数据时,sum distinct应该返回NULL, 而不是0,因为0对sum聚合函数来说是有意义的数。单个sum distinct计算结果没有问题,但是多个sum distinct的计算结果有问题。

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