本文整理了Java中java.security.Security.renumProviders()方法的一些代码示例，展示了Security.renumProviders()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Security.renumProviders()方法的具体详情如下：
包路径：java.security.Security
类名称：Security
方法名：renumProviders

Security.renumProviders介绍

[英]Update sequence numbers of all providers.
[中]更新所有提供者的序列号。

代码示例

代码示例来源：origin: robovm/robovm

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: robovm/robovm

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: ibinti/bugvm

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: MobiVM/robovm

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: com.mobidevelop.robovm/robovm-rt

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: FlexoVM/flexovm

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: com.bugvm/bugvm-rt

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: com.gluonhq/robovm-rt

/**
 * Insert the given {@code Provider} at the specified {@code position}. The
 * positions define the preference order in which providers are searched for
 * requested algorithms.
 *
 * @param provider
 *            the provider to insert.
 * @param position
 *            the position (starting from 1).
 * @return the actual position or {@code -1} if the given {@code provider}
 *         was already in the list. The actual position may be different
 *         from the desired position.
 */
public static synchronized int insertProviderAt(Provider provider, int position) {
  // check that provider is not already
  // installed, else return -1; if (position <1) or (position > max
  // position) position = max position + 1; insert provider, shift up
  // one position for next providers; Note: The position is 1-based
  if (getProvider(provider.getName()) != null) {
    return -1;
  }
  int result = Services.insertProviderAt(provider, position);
  renumProviders();
  return result;
}

代码示例来源：origin: MobiVM/robovm

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: ibinti/bugvm

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: FlexoVM/flexovm

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: com.bugvm/bugvm-rt

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: com.mobidevelop.robovm/robovm-rt

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}

代码示例来源：origin: com.gluonhq/robovm-rt

/**
 * Removes the {@code Provider} with the specified name form the collection
 * of providers. If the the {@code Provider} with the specified name is
 * removed, all provider at a greater position are shifted down one
 * position.
 *
 * <p>Returns silently if {@code name} is {@code null} or no provider with the
 * specified name is installed.
 *
 * @param name
 *            the name of the provider to remove.
 */
public static synchronized void removeProvider(String name) {
  // It is not clear from spec.:
  // 1. if name is null, should we checkSecurityAccess or not?
  //    throw SecurityException or not?
  // 2. as 1 but provider is not installed
  // 3. behavior if name is empty string?
  Provider p;
  if ((name == null) || (name.length() == 0)) {
    return;
  }
  p = getProvider(name);
  if (p == null) {
    return;
  }
  Services.removeProvider(p.getProviderNumber());
  renumProviders();
  p.setProviderNumber(-1);
}