js实现页面跳转与参数获取加载

x33g5p2x  于2022-07-26 转载在 其他  
字(1.3k)|赞(0)|评价(0)|浏览(279)

1 页面跳转

location.replace("/search?q=" + keyword);

2 获取请求详细信息

let url = window.location.href; //获取当前窗口的Url;  结果:http://127.0.0.1:8081/search?q=Python
let host = window.location.host;//获取当前窗口的主机名;   结果:127.0.0.1:8081
let port = window.location.port; //获取当前窗口的端口; 结果:8081
let pathname = window.location.pathname;//获取当前窗口的路径 ; 结果:/search
let URL = document.URL;//获取当前文档的Url;结果:http://127.0.0.1:8081/search?q=Python
let search1 = window.location.search;//获取参数;结果:?q=Python
let origin = window.location.origin;//获取来源地址;结果:http://127.0.0.1:8081
let protocol = window.location.protocol;//获取协议;结果:http:

console.log("-------------")
console.log(url)
console.log(host)
console.log(port)
console.log(pathname)
console.log(URL)
console.log(search1)
console.log(origin)
console.log(protocol)

2 获取携带参数

函数

//key(需要检索的键) url(传入的需要分割的url地址,例:?id=2&age=18)
function getSearchString(key, Url) {
	var str = Url;
	str = str.substring(1, str.length); // 获取URL中?之后的字符(去掉第一位的问号)
	// 以&分隔字符串,获得类似name=xiaoli这样的元素数组
	var arr = str.split("&");
	var obj = new Object();
	// 将每一个数组元素以=分隔并赋给obj对象
	for (var i = 0; i < arr.length; i++) {
	    var tmp_arr = arr[i].split("=");
	    obj[decodeURIComponent(tmp_arr[0])] = decodeURIComponent(tmp_arr[1]);
	}
	return obj[key];
}

调用

let search = window.location.search;
let q = getSearchString('q', search); //结果:云原生
console.log(q)
$("#keyword").val(q)

参考地址:
https://blog.csdn.net/Neil_clip/article/details/120972562

相关文章

微信公众号

最新文章

更多