我在awsaglue(版本1.0)中有一个python3作业,它启用了书签。此作业将json数据源转换为s3 bucket中的parquet文件格式。这项工作运行完美的第一次,或者如果我重置书签。
但是,后续运行会失败,并出现以下错误。
analysisexception:“\n数据源不支持写入空的或嵌套的空架构。\n请确保数据架构至少有一列或多列。\n;”
所使用的脚本是由aws控制台生成的,没有任何修改,源代码是使用data catalog的s3 bucket中的json文件,输出是另一个bucket。
import sys
from awsglue.transforms import *
from awsglue.utils import getResolvedOptions
from pyspark.context import SparkContext
from awsglue.context import GlueContext
from awsglue.job import Job
## @params: [JOB_NAME]
args = getResolvedOptions(sys.argv, ['JOB_NAME'])
sc = SparkContext()
glueContext = GlueContext(sc)
spark = glueContext.spark_session
job = Job(glueContext)
job.init(args['JOB_NAME'], args)
## @type: DataSource
## @args: [database = "segment", table_name = "segment_zlw54zvojf", transformation_ctx = "datasource0"]
## @return: datasource0
## @inputs: []
datasource0 = glueContext.create_dynamic_frame.from_catalog(database = "segment", table_name = "segment_zlw54zvojf", transformation_ctx = "datasource0")
## @type: ApplyMapping
## @args: [mapping = [("channel", "string", "channel", "string"), ("context", "struct", "context", "struct"), ("event", "string", "event", "string"), ("integrations", "struct", "integrations", "struct"), ("messageid", "string", "messageid", "string"), ("projectid", "string", "projectid", "string"), ("properties", "struct", "properties", "struct"), ("receivedat", "string", "receivedat", "string"), ("timestamp", "string", "timestamp", "string"), ("type", "string", "type", "string"), ("userid", "string", "userid", "string"), ("version", "int", "version", "int"), ("anonymousid", "string", "anonymousid", "string"), ("partition_0", "string", "partition_0", "string")], transformation_ctx = "applymapping1"]
## @return: applymapping1
## @inputs: [frame = datasource0]
applymapping1 = ApplyMapping.apply(frame = datasource0, mappings = [("channel", "string", "channel", "string"), ("context", "struct", "context", "struct"), ("event", "string", "event", "string"), ("integrations", "struct", "integrations", "struct"), ("messageid", "string", "messageid", "string"), ("projectid", "string", "projectid", "string"), ("properties", "struct", "properties", "struct"), ("receivedat", "string", "receivedat", "string"), ("timestamp", "string", "timestamp", "string"), ("type", "string", "type", "string"), ("userid", "string", "userid", "string"), ("version", "int", "version", "int"), ("anonymousid", "string", "anonymousid", "string"), ("partition_0", "string", "partition_0", "string")], transformation_ctx = "applymapping1")
## @type: ResolveChoice
## @args: [choice = "make_struct", transformation_ctx = "resolvechoice2"]
## @return: resolvechoice2
## @inputs: [frame = applymapping1]
resolvechoice2 = ResolveChoice.apply(frame = applymapping1, choice = "make_struct", transformation_ctx = "resolvechoice2")
## @type: DropNullFields
## @args: [transformation_ctx = "dropnullfields3"]
## @return: dropnullfields3
## @inputs: [frame = resolvechoice2]
dropnullfields3 = DropNullFields.apply(frame = resolvechoice2, transformation_ctx = "dropnullfields3")
## @type: DataSink
## @args: [connection_type = "s3", connection_options = {"path": "s3://mydestination.datalake.raw/segment/iterable"}, format = "parquet", transformation_ctx = "datasink4"]
## @return: datasink4
## @inputs: [frame = dropnullfields3]
datasink4 = glueContext.write_dynamic_frame.from_options(frame = dropnullfields3, connection_type = "s3", connection_options = {"path": "s3://mydestination.datalake.raw/segment/iterable"}, format = "parquet", transformation_ctx = "datasink4")
job.commit()
任何建议都将不胜感激。
1条答案
按热度按时间ujv3wf0j1#
所以我把这个问题搞清楚了。
根据源s3,bucket每天都有新的数据写入其中。但是,这些数据会写入我的s3存储桶中的新子文件夹中。
为了让这些新的子文件夹被aws glue作业识别,我需要重新运行aws crawler来更新源数据目录。
如果不这样做,就不会识别新的数据,并且默认的aws生成的脚本尝试写入空数据集,但失败了。
为了解决这个问题,我计划在执行作业之前执行爬虫。