我在我的主页上通过ajax异步运行了以下.php文件,该主页本应提交评论:
<?php
session_start();
include "dxbase.php";
$conn = new mysqli($servername, $username, $password, $dbname);
$comment = "practice";
$prid = 2;
if(isset($_SESSION['user'])){
$usera = $_SESSION['user'];
$stmt = $conn->prepare("INSERT INTO reviews (prid, content, username) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $prid, $comment, $usera);
$stmt->execute();
echo "Review submitted!";
$stmt->close();
} else {
echo "Oops! You need to be signed in to review products!";
}
$conn->close();
?>
当我运行它时,它回显它已经提交了一条评论,但当我检查我的数据库时,它不在那里:db
为什么不插?!
暂无答案!
目前还没有任何答案,快来回答吧!