我在查询mysql数据库时得到一个空集

hsgswve4  于 2021-06-21  发布在  Mysql
关注(0)|答案(1)|浏览(279)

我最近有一个问题让我发疯,每当我试图查询数据库时,总是得到一个空的结果!
请帮助,我在这里为任何更多的信息或细节。
这是数据库类:

final class database
{

    private const DB_HOST     =   'localhost';
    private const DB_NAME     =   'branches';
    private const DB_CHARSET  =   'utf8';
    private const DB_USER     =   'public_user';
    private const DB_PASS     =   '1y37*V9ddGd@';
    public const EMAIL_TO    =   'someone@gmail.com';

    public static function database_connect()
    {
            // setting DSN (Data Source Name)
            $dsn = 'mysql:host=' . self::DB_HOST . ';' . 'charset=' . self::DB_CHARSET;

        try {

            // creating a PDO (PHP Data Object) instance
            $pdo = new PDO($dsn, self::DB_USER, self::DB_PASS);
            $pdo->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);

            return $pdo;

        } catch (PDOException $e) {

            if (DEBUG === true) {

                echo "<pre><br><var>";
                print_r('An error has occured during database connection initiation Big Boss: <br> ' . $e);
                echo "</var></pre><br>";

            } else {

                $headers  = "From: admin@company.com" . "\r\n";
                $headers .= "Reply-To: No One" . "\r\n";
                $headers .= "MIME-Version: 1.0\r\n";
                $headers .= "Content-Type: text/html; charset=UTF-8\r\n";

                if (mail(self::EMAIL_TO, 'An error has occured', $e, $headers)) {

                    echo 'المعذرة حدث خطاء فادح! لقد تم إرسال الخطاء إلى مطور الموقع لمعالجتة.';

                } else {

                    echo 'الرجاء التواصل مع مدير موقع شركة الجزيرة إخوان للصرافة على الإيميل التالي: <br>
                    someone@gmail.com';

                }

            }

        }

    }

    private function __clone() {}
}

我就是这样从索引页查询数据库的:

<?php
  $connection = Database::database_connect();
  $select_database = "use branches";
  Database::database_query($connection, $select_database);
                        $get_all_branches_query = "SELECT * FROM jazz_branches_ar WHERE branch_status = 1";
                        $query_results = Database::database_query($connection, $get_all_branches_query);
                        foreach ($query_results as $branch) {
                            echo "<tr>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_fax'])))) , "</td>";
                                echo "<td><a class=\"inline-links\" href=\"tel:", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))), "\">", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))) ,"</a></td>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_address'])))), "</td>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_city'])))), "</td>";
                            echo "</tr>";
                        }
                        ?>

笔记:
我正在使用与戈达迪共享主机。
我在下面添加的旧代码曾经工作得很好。
这是我以前的数据库类,您可以看到它忽略了各种安全措施:

class Database
{
    private static $_db_host = 'mysql:host=localhost;charset=utf8';
    private static $_db_user = 'jazz_god';
    private static $_db_pass = 'LcaQVNH3qz6Cksow';
    public static function database_connect() 
    {
        return $db_info = new PDO(Database::$_db_host, Database::$_db_user, Database::$_db_pass);
    }
    public static function database_query($db_connection, $query) 
    {
        $statment = $db_connection->prepare($query);
        $statment->execute();
        $result = $statment->fetchAll(PDO::FETCH_ASSOC);
        return $result;
    }
}

这是用来查询数据库的代码:

<?php
                    $connection = Database::database_connect();
                    $select_database = $connection->prepare('use jazz_agents_branches');
                    $select_database->execute();
                    $get_all_branches_query = "SELECT * FROM jazz_branches_ar WHERE branch_status = 1";
                    $query_results = Database::database_query($connection, $get_all_branches_query);
                    foreach ($query_results as $branch) {
                        echo "<tr>";
                            echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_fax'])))) , "</td>";
                            echo "<td><a class=\"inline-links\" href=\"tel:", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))), "\">", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))) ,"</a></td>";
                            echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_address'])))), "</td>";
                            echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_city'])))), "</td>";
                        echo "</tr>";
                    }
                    ?>

尽管我将我的应用程序置于危险之中,但我决定在下面列出我使用的库和php版本:

yizd12fk

yizd12fk1#

把这个:

$dsn = 'mysql:host=' . self::DB_HOST . ';' . 'charset=' . self::DB_CHARSET;

在尝试中:

$connection = database::database_connect();
 $select_database = $connection->prepare('use branches');
 $select_database->execute();

您的代码必须是:

<?php
  $connection = Database::database_connect();
  $select_database = "use branches";
  Database::database_query($connection, $select_database);
                        $get_all_branches_query = "SELECT * FROM jazz_branches_ar WHERE branch_status = 1";
                        $query_results = Database::database_query($connection, $get_all_branches_query);
                        foreach ($query_results as $branch) {
                            echo "<tr>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_fax'])))) , "</td>";
                                echo "<td><a class=\"inline-links\" href=\"tel:", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))), "\">", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_tel'])))) ,"</a></td>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_address'])))), "</td>";
                                echo "<td>", htmlspecialchars(strip_tags(stripslashes(trim($branch['branch_city'])))), "</td>";
                            echo "</tr>";
                        }
                        ?>

类的电子邮件错误将电子邮件更改为public您无法访问类的私有属性:

public const EMAIL_TO    =   'someone@gmail.com';

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