Java8—从给定项开始截断列表中所有项的最佳方法

ego6inou 于 2021-06-26 发布在 Java

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给定一个car类型的对象列表，从某个值开始截断列表最复杂的方法（使用java8）是什么？
例子：

Class Car {
   String name;
   public Car(String name) {
       this.name = name;
   }
}

List<Car> cars = new ArrayList();
cars.add(new Car("Accord"));
cars.add(new Car("Civic"));
cars.add(new Car("CRV"));
cars.add(new Car("Corolla"));
cars.add(new Car("Camry"));
cars.add(new Car("Forerunner"));

Input:["Accord", "Civic", "CRV", "Corolla", "Camry", "Forerunner"], "Corolla"
Expected Output: ["Camry", "Forerunner"]

Java java-stream Iterator functional-programming java-8

来源：https://stackoverflow.com/questions/65605234/java-8-best-way-to-truncate-all-items-of-a-list-starting-from-a-given-item

3条答案

按热度按时间

odopli941#

首先找到要查找的元素的索引，然后根据该索引创建子列表：

List<Car> cars = new ArrayList();
            cars.add(new Car("Accord"));
            cars.add(new Car("Civic"));
            cars.add(new Car("CRV"));
            cars.add(new Car("Corolla"));
            cars.add(new Car("Camry"));
            cars.add(new Car("Forerunner"));

            int index = cars.stream()
                             .map(car -> car.name)
                             .collect(Collectors.toList())
                             .indexOf("Corolla");
            List<Car> trimedCarList = cars.subList(index+1,cars.size());
            trimedCarList.forEach(car -> System.out.println(car.name));

赞(0）回复(0）举报 2021-06-26

pxq42qpu2#

你在找以下的东西吗？
我故意让它简单，即使用字符串而不是 Car 对象，因为 Car 对象实际上与任务无关，因此这对于其他人来说也更通用。

private static List<String> subListAfter(List<String> values, String startAfter) {
    int idx = values.indexOf(startAfter);
    return (idx == -1 ? Collections.emptyList() : values.subList(idx + 1, values.size()));
}

测试

List<String> wordList = Arrays.asList("Accord", "Civic", "CRV", "Corolla", "Camry", "Forerunner");
System.out.println(subListAfter(wordList, "Corolla"));

输出