将列值除以impala中的总行数

nwsw7zdq  于 2021-06-26  发布在  Impala
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select count(distinct cgi.sample)由于impala不允许set操作或select语句中的子查询,我很难弄清楚如何用返回的行总数除以列值。我的最终目标是计算每个基因的次要等位基因频率chr:start position.
我的数据结构如下:

| chr | start    | stop     | ref | allele1seq | allele2seq | sample_id | 
|  6  | 66720709 | 66720710 |  A  |      A     |     T      | 101-46-3  |
|  7  | 66720809 | 66720810 |  GG |      GA    |     GG     | 101-46-3  |

我想做一些类似于下面的查询:

WITH vars as
(SELECT cgi.chr, cgi.start, concat(cgi.chr, ':', CAST(cgi.start AS STRING)) as pos, cgi.ref, cgi.allele1seq, cgi.allele2seq,
    CASE 
        WHEN (cgi.allele1seq = cgi.ref AND cgi.allele2seq <> cgi.ref) THEN '1'  
        WHEN (cgi.allele1seq <> cgi.ref AND cgi.allele2seq = cgi.ref) THEN '1' 
        WHEN (cgi.allele1seq = cgi.ref AND cgi.allele2seq = cgi.ref) THEN '2' 
        ELSE '0' END as ma_count
    FROM comgen_variants as cgi)

SELECT vars.*, (CAST(vars.ma_count as INT)/
((SELECT COUNT(DISTINCT cgi.sample_id) from comgen_variants as cgi) * 2)) as maf
FROM vars

我想要的输出是:

| chr | start    | ref | allele1seq | allele2seq | ma_count | maf |  
|  6  | 66720709 |  A  |      A     |     T      |     1    | .05 | 
|  7  | 66720809 |  GG |      GG    |     GG     |     0    |  0  |

除了找出一种除以行数的方法外,我还需要将结果按chr和pos分组,然后计算每个备用等位基因(其中等位基因1seq和等位基因2seq不等于ref)出现的次数,而不是像上面那样简单地按行计数;但我还没到那一步,因为计数的问题。
事先谢谢你的帮助。

vqlkdk9b

vqlkdk9b1#

看起来你可以计算出 total number of distinct sample_ids*2 然后将其用于后续查询,因为每行的值不会更改。如果该值确实依赖于行,那么您可能需要查看impala可用的分析/窗口函数。
但是,既然看起来你不需要这样做,你可以做如下的事情:

WITH total AS 
(SELECT COUNT(DISTINCT sample_id) * 2 AS total FROM comgen_variants)

SELECT cgi.*,
       (CASE 
          WHEN (cgi.allele1seq = cgi.ref AND cgi.allele2seq <> cgi.ref) THEN 1  
          WHEN (cgi.allele1seq <> cgi.ref AND cgi.allele2seq = cgi.ref) THEN 1 
          WHEN (cgi.allele1seq = cgi.ref AND cgi.allele2seq = cgi.ref) THEN 2
          ELSE 0 END) / total.total AS maf
FROM comgen_variants AS cgi, total;

不过,我不确定次要等位基因的频率是多少;似乎你想为每个基因座选择第二个最常见的等位基因频率?

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