spark bigtable-hbase客户端没有在pyspark中关闭?

ev7lccsx  于 2021-07-13  发布在  Hbase
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我正在尝试执行一个pyspark语句,该语句在python for循环中写入bigtable,这将导致以下错误(使用dataproc提交的作业)。任何客户没有正确关闭(如这里所建议的),如果是,有什么办法在pyspark中这样做?
请注意,每次使用新的dataproc作业手动重新执行脚本都可以正常工作,因此作业本身是正确的。
谢谢你的支持!
Pypark脚本

from pyspark import SparkContext 
from pyspark.sql import SQLContext 
import json

sc = SparkContext()
sqlc = SQLContext(sc) 

def create_df(n_start,n_stop):

    # Data

    row_1 = ['a']+['{}'.format(i) for i in range(n_start,n_stop)]
    row_2 = ['b']+['{}'.format(i) for i in range(n_start,n_stop)]

    # Spark schema

    ls = [row_1,row_2]
    schema = ['col0'] + ['col{}'.format(i) for i in range(n_start,n_stop)]

    # Catalog

    first_col = {"col0":{"cf":"rowkey", "col":"key", "type":"string"}}
    other_cols =  {"col{}".format(i):{"cf":"cf", "col":"col{}".format(i), "type":"string"} for i in range(n_start,n_stop)}

    first_col.update(other_cols)
    columns = first_col

    d_catalogue = {}
    d_catalogue["table"] = {"namespace":"default", "name":"testtable"}
    d_catalogue["rowkey"] = "key"
    d_catalogue["columns"] = columns

    catalog = json.dumps(d_catalogue)

    # Dataframe

    df = sc.parallelize(ls, numSlices=1000).toDF(schema=schema) 

    return df,catalog

for i in range(0,2):

   N_step = 100
   N_start = 1
   N_stop = N_start+N_step

   data_source_format = "org.apache.spark.sql.execution.datasources.hbase"

   df,catalog = create_df(N_start,N_stop)

   df.write\
        .options(catalog=catalog,newTable= "5")\
            .format(data_source_format)\
                .save()

   N_start += N_step
   N_stop += N_step

dataproc作业

gcloud dataproc jobs submit pyspark <my_script>.py \
    --cluster $SPARK_CLUSTER \
        --jars <path_to_jar>/bigtable-dataproc-spark-shc-assembly-0.1.jar \
            --region=us-east1

错误

...
ERROR com.google.bigtable.repackaged.io.grpc.internal.ManagedChannelOrphanWrapper: *~*~*~ Channel ManagedChannelImpl{logId=41, target=bigtable.googleapis.com:443} was not shutdown properly!!! ~*~*~*
    Make sure to call shutdown()/shutdownNow() and wait until awaitTermination() returns true.
...
kiz8lqtg

kiz8lqtg1#

如果您没有使用最新版本,请尝试更新它。它看起来类似于最近修复的这个问题。我可以想象错误信息仍然会出现,但是现在完成的工作意味着支持团队仍在处理它,希望他们能在下一个版本中修复它。

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