我的方法是3路实现：（使用jpa和hibernate）
用户请求上下文
获取上下文的Map超类
一个语句检查器来注入你的用户ID
例如：

public final class UserRequestContext {
  public static String getUserId() {
    // code to retrieve your userid and throw when there is none!
    if (userId == null) throw new IllegalStateException("userid null");
    return userId;
  }
}

@MappedSuperclass
public class UserResolver {
  public static final String USER_RESOLVER = "USER_RESOLVER";

  @Access(AccessType.PROPERTY)
  public String getUserId() {
    return UserRequestContext.getUserId();
  }

}

@Component
public class UserInspector implements StatementInspector {
  @Override
  public String inspect(String statement) {
    if (statement.contains(UserResolver.USER_RESOLVER)) {
       statement = statement.replace(UserResolver.USER_RESOLVER, "userId = '" + UserRequestContext.getUserId() + "'" );
    }
    return sql;
  }

  @Bean
  public HibernatePropertyCustomizer hibernatePropertyCustomizer() {
    return hibernateProperies -> hibernateProperties.put("hibernate.session_factory.statement_inspector", 
    UserInspector.class.getName());
  }
}

所以你的实体看起来像这样：

@Entity
...
@Where(clause = UserResolver.USER_RESOLVER)
public class Todo extends UserResolver {
   ...
}