spring grpc-如何用body info截获异常

svujldwt  于 2021-07-26  发布在  Java
关注(0)|答案(1)|浏览(433)

我有一个使用springgrpc的项目。我创建了一个拦截器,当服务成功响应时,拦截器工作正常,但当服务捕获异常时,拦截器不工作。
服务:

@GrpcService
public class ClientAppImpl extends ClientAppGrpc.ClientAppImplBase {

    @Autowired MyService myService;

    @Override
    public void myMethod(Request request, StreamObserver<CreateDigitalCertificateResponse> responseObserver) {
        try {
            Response response = myService.doStuff(request);
            responseObserver.onNext(response);
            responseObserver.onCompleted();
        } catch(Exception ex) {
            responseObserver.onError(Status.INTERNAL.withDescription(exception.getMessage()).withCause(exception).asRuntimeException());
        }

    }
}

拦截器:

@GrpcGlobalServerInterceptor
public class GrpcServerInterceptor implements ServerInterceptor {

    public static final String REQUEST_ID_HEADER = "request-id-bin";
    public static final Metadata.Key<byte[]> REQUEST_ID_METADATA_KEY = Metadata.Key.of(REQUEST_ID_HEADER, Metadata.BINARY_BYTE_MARSHALLER);
    private static final Map<String, GrpcCall> CALLS = new HashMap<>();

    @Override
    public <ReqT, RespT> ServerCall.Listener<ReqT> interceptCall(ServerCall<ReqT, RespT> call, Metadata headers, ServerCallHandler<ReqT, RespT> next) {

        ForwardingServerCall<ReqT, RespT> responseServerCall = new ForwardingServerCall.SimpleForwardingServerCall<ReqT, RespT>(call) {
            @Override
            public void sendMessage(RespT response) {
                String callId = new String(headers.get(REQUEST_ID_METADATA_KEY));

                GrpcCall grpcCall = CALLS.get(callId);
                grpcCall.setResponse(response);

                GrpcCallProcessor grpcCallProcessor = new GrpcCallProcessor(grpcCall);
                grpcCallProcessor.processCall();

                super.sendMessage(response);
            }

        };

        ServerCall.Listener<ReqT> listenerWithContext = Contexts.interceptCall(Context.current(), responseServerCall, headers, next);

        return new ForwardingServerCallListener.SimpleForwardingServerCallListener<ReqT>(listenerWithContext) {

            @Override
            public void onMessage(ReqT request) {
                String callId = UUID.randomUUID().toString();

                headers.put(REQUEST_ID_METADATA_KEY, callId.getBytes());

                GrpcCall grpcCall = new GrpcCall();
                grpcCall.setCall(call);
                grpcCall.setHeaders(headers);
                grpcCall.setRequest(request);

                CALLS.put(callId, grpcCall);

                super.onMessage(request);
            }
        };
    }
}

当服务未捕获异常时,拦截器工作正常,并调用sendmessage方法。但是当服务捕捉到异常时,不会调用sendmessage方法。
是否有任何方法可以拦截异常,并在拦截器中获取de-request body?
谢谢!

9o685dep

9o685dep1#

如果 myService.doStuff() 抛出异常,没有发送任何消息。 sendMessage() 不会打电话的,但是 close(Status, Metadata) 还是会的。
的当前用法 headers 它坏了。 Metadata 不是线程安全的,并且您不知道对象的当前“所有者”正在使用它做什么。 headers.get(REQUEST_ID_METADATA_KEY) 应在 interceptCall() 直接,在回来之前。
现在还不完全清楚 onMessage() 是的,但看起来你应该复制一份元数据( new Metadata().merge(headers )内 interceptCall() .

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