sql函数卡住,不会返回值

qxsslcnc  于 2021-07-26  发布在  Java
关注(0)|答案(1)|浏览(337)

我有一个相当简单的函数,它接受一个字符串,检查值并替换它们,在所有替换之后返回结果字符串。没有回路什么的。
但是,当我运行它时,它就像被卡在循环中一样,不会返回任何值。
以下是相关功能:

ALTER FUNCTION [dbo].[fn_DeNormalizeCo] (@oldStr varchar(255))
    RETURNS varchar(255)
BEGIN
    DECLARE 
        @newStr varchar(255)

    SET @newStr = LTRIM(RTRIM(@oldStr))

    -- Tab  \t
    IF (@newStr LIKE '%'+CHAR(9)+'%')
        SET @newStr = REPLACE(@newStr, CHAR(9), '')

    -- Linefeed \n
    IF (@newStr LIKE '%'+CHAR(10)+'%')
        SET @newStr = REPLACE(@newStr, CHAR(10), '')

    -- Carriage Return \r
    IF (@newStr LIKE '%'+CHAR(13)+'%')
        SET @newStr = REPLACE(@newStr, CHAR(13), '')

    -- °
    IF (@newStr LIKE '%'+CHAR(176)+'%')
        SET @newStr = REPLACE(@newStr, CHAR(176), '')

    IF (@newStr LIKE '%#%')
        SET @newStr = REPLACE(@newStr, '#', '')

    IF (@newStr LIKE '%:%')
        SET @newStr = REPLACE(@newStr, ':', '')

    IF (@newStr LIKE '%;%')
        SET @newStr = REPLACE(@newStr, ';', '')

    IF (@newStr LIKE '%@%')
        SET @newStr = REPLACE(@newStr, '@', '')

    IF (@newStr LIKE '%[%]%')
        SET @newStr = REPLACE(@newStr, '%', '')

    IF (@newStr LIKE '%*%')
        SET @newStr = REPLACE(@newStr, '*', '')

    IF (@newStr LIKE '%&%')
        SET @newStr = REPLACE(@newStr, '&', '')

    IF (@newStr LIKE '%!%')
        SET @newStr = REPLACE(@newStr, '!', '')

    IF (@newStr LIKE '%$%')
        SET @newStr = REPLACE(@newStr, '$', '')

    IF (@newStr LIKE '%"%')
        SET @newStr = REPLACE(@newStr, '"', '')

    IF (@newStr LIKE '%''%')
        SET @newStr = REPLACE(@newStr, '''', '')

    IF (@newStr LIKE '%,INC.%')
        SET @newStr = REPLACE(@newStr, ',INC.', '')

    IF (@newStr LIKE '%,INC%')
        SET @newStr = REPLACE(@newStr, ',INC', '')

    IF (@newStr LIKE '%, INC.%')
        SET @newStr = REPLACE(@newStr, ', INC.', '')

    IF (@newStr LIKE '%, INC%')
        SET @newStr = REPLACE(@newStr, ', INC', '')

    IF (@newStr LIKE '% INC.')
        SET @newStr = REPLACE(@newStr, ' INC.', '')

    IF (@newStr LIKE '% INC')
        SET @newStr = REPLACE(@newStr, ' INC', '')

    IF (@newStr LIKE '%,LLC.%')
        SET @newStr = REPLACE(@newStr, ',LLC.', '')

    IF (@newStr LIKE '%,LLC%')
        SET @newStr = REPLACE(@newStr, ',LLC', '')

    IF (@newStr LIKE '%, LLC.%')
        SET @newStr = REPLACE(@newStr, ', LLC.', '')

    IF (@newStr LIKE '%, LLC%')
        SET @newStr = REPLACE(@newStr, ', LLC', '')

    IF (@newStr LIKE '%LLC.')
        SET @newStr = REPLACE(@newStr, ' LLC.', '')

    IF (@newStr LIKE '% LLC')
        SET @newStr = REPLACE(@newStr, ' LLC', '')

    IF (@newStr LIKE '%,CO.%')
        SET @newStr = REPLACE(@newStr, ',CO.', '')

    IF (@newStr LIKE '%,CO%')
        SET @newStr = REPLACE(@newStr, ',CO', '')

    IF (@newStr LIKE '%, CO.%')
        SET @newStr = REPLACE(@newStr, ', CO.', '')

    IF (@newStr LIKE '%, CO%')
        SET @newStr = REPLACE(@newStr, ', CO', '')

    IF (@newStr LIKE '% CO.%') 
        SET @newStr = REPLACE(@newStr, ' CO.', '')

    IF (@newStr LIKE '% CO%') 
        SET @newStr = REPLACE(@newStr, ' CO', '')

    IF (@newStr LIKE '%,CORP.')
        SET @newStr = REPLACE(@newStr, ',CORP.', '')

    IF (@newStr LIKE '%,CORP')
        SET @newStr = REPLACE(@newStr, ',CORP', '')

    IF (@newStr LIKE '%, CORP.')

        SET @newStr = REPLACE(@newStr, ', CORP.', '')

    IF (@newStr LIKE '%, CORP')
        SET @newStr = REPLACE(@newStr, ', CORP', '')

    IF (@newStr LIKE '% CORP.')
        SET @newStr = REPLACE(@newStr, ' CORP.', '')

    IF (@newStr LIKE '% CORP')
        SET @newStr = REPLACE(@newStr, ' CORP', '')

    IF (@newStr LIKE '%,MFG.')
        SET @newStr = REPLACE(@newStr, ',MFG.', '')

    IF (@newStr LIKE '%,MFG')
        SET @newStr = REPLACE(@newStr, ',MFG', '')

    IF (@newStr LIKE '%, MFG.')
        SET @newStr = REPLACE(@newStr, ', MFG.', '')

    IF (@newStr LIKE '%, MFG')
        SET @newStr = REPLACE(@newStr, ', MFG', '')

    IF (@newStr LIKE '% MFG.')
        SET @newStr = REPLACE(@newStr, ' MFG.', '')

    IF (@newStr LIKE '% MFG')
        SET @newStr = REPLACE(@newStr, ' MFG', '')

    IF (@newStr LIKE '%,INCORPORATED.%')
        SET @newStr = REPLACE(@newStr, ',INCORPORATED.', '')

    IF (@newStr LIKE '%,INCORPORATED%')
        SET @newStr = REPLACE(@newStr, ',INCORPORATED', '')

    IF (@newStr LIKE '%, INCORPORATED.%')
        SET @newStr = REPLACE(@newStr, ', INCORPORATED.', '')

    IF (@newStr LIKE '%, INCORPORATED%')
        SET @newStr = REPLACE(@newStr, ', INCORPORATED', '')

    IF (@newStr LIKE '% INCORPORATED.')
        SET @newStr = REPLACE(@newStr, 'INCORPORATED.', '')

    IF (@newStr LIKE '% INCORPORATED')
        SET @newStr = REPLACE(@newStr, 'INCORPORATED', '')

    RETURN @newStr
END

我试过一个简单的电话: SELECT [ULTRA].[dbo].[fn_DeNormalizeCo]('Noname LLC') 为了排除从另一个数据库调用函数的可能性,我还尝试了使用 SELECT [dbo].[fn_DeNormalizeCo]('Noname LLC') 和被卡住的结果一样。
我在这里真的很茫然,我发誓在我必须擦除和重新加载我的电脑之前,我已经很好地使用了这个功能。
我正在使用:
sql server 2019(v15.0.2070.41)
ssms版本18.5

oo7oh9g9

oo7oh9g91#

因为您使用的是sql server 2019,所以可能值得一试

alter function [dbo].[fn_DeNormalizeCo] (@oldStr varchar(255)) 
returns varchar(255) 
with inline = OFF

.. 如果数据库兼容级别为150并启用了内联。
标量内联仍然是已知的bug。

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