我想从我的ubuntu系统中的一个文件夹启动一个php服务器，我尝试了以下命令。

php -S localhost:8000

但它没有启动服务器。我得到了以下输出

Usage: php [options] [-f] <file> [--] [args...]
       php [options] -r <code> [--] [args...]
       php [options] [-B <begin_code>] -R <code> [-E <end_code>] [--] [args...]
       php [options] [-B <begin_code>] -F <file> [-E <end_code>] [--] [args...]
       php [options] -- [args...]
       php [options] -a

  -a               Run as interactive shell
  -c <path>|<file> Look for php.ini file in this directory
  -n               No php.ini file will be used
  -d foo[=bar]     Define INI entry foo with value 'bar'
  -e               Generate extended information for debugger/profiler
  -f <file>        Parse and execute <file>.
  -h               This help
  -i               PHP information
  -l               Syntax check only (lint)
  -m               Show compiled in modules
  -r <code>        Run PHP <code> without using script tags <?..?>
  -B <begin_code>  Run PHP <begin_code> before processing input lines
  -R <code>        Run PHP <code> for every input line
  -F <file>        Parse and execute <file> for every input line
  -E <end_code>    Run PHP <end_code> after processing all input lines
  -H               Hide any passed arguments from external tools.
  -s               Output HTML syntax highlighted source.
  -v               Version number
  -w               Output source with stripped comments and whitespace.
  -z <file>        Load Zend extension <file>.

  args...          Arguments passed to script. Use -- args when first argument
                   starts with - or script is read from stdin

  --ini            Show configuration file names

  --rf <name>      Show information about function <name>.
  --rc <name>      Show information about class <name>.
  --re <name>      Show information about extension <name>.
  --ri <name>      Show configuration for extension <name>.

但我在谷歌上搜索了很多次，都没有找到任何解决方案。我应该如何进行？请帮助