Would you like to submit a PR to improve relevant logic?

确实是这样的，我的服务A运行在docker内，服务注册到nacos上面，nacos显示的就是物理网卡的ip，同时注册到sentinel控制台，sentinel就显示的是虚拟ip。
sentinel获取ip的逻辑在com.alibaba.csp.sentinel.util.HostNameUtil.java里面：

private static void resolveHost() throws Exception {
        InetAddress addr = InetAddress.getLocalHost();
        hostName = addr.getHostName();
        ip = addr.getHostAddress();
        if (addr.isLoopbackAddress()) {
            // find the first IPv4 Address that not loopback
            Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
            while (interfaces.hasMoreElements()) {
                NetworkInterface in = interfaces.nextElement();
                Enumeration<InetAddress> addrs = in.getInetAddresses();
                while (addrs.hasMoreElements()) {
                    InetAddress address = addrs.nextElement();
                    if (!address.isLoopbackAddress() && address instanceof Inet4Address) {
                        ip = address.getHostAddress();
                    }
                }
            }
        }
    }

nacos获取ip的的逻辑在org.springframework.cloud.commons.util.InetUtils.java里面：

public InetAddress findFirstNonLoopbackAddress() {
		InetAddress result = null;
		try {
			int lowest = Integer.MAX_VALUE;
			for (Enumeration<NetworkInterface> nics = NetworkInterface
					.getNetworkInterfaces(); nics.hasMoreElements();) {
				NetworkInterface ifc = nics.nextElement();
				if (ifc.isUp()) {
					this.log.trace("Testing interface: " + ifc.getDisplayName());
					if (ifc.getIndex() < lowest || result == null) {
						lowest = ifc.getIndex();
					}
					else if (result != null) {
						continue;
					}

					// @formatter:off
					if (!ignoreInterface(ifc.getDisplayName())) {
						for (Enumeration<InetAddress> addrs = ifc
								.getInetAddresses(); addrs.hasMoreElements();) {
							InetAddress address = addrs.nextElement();
							if (address instanceof Inet4Address
									&& !address.isLoopbackAddress()
									&& isPreferredAddress(address)) {
								this.log.trace("Found non-loopback interface: "
										+ ifc.getDisplayName());
								result = address;
							}
						}
					}
					// @formatter:on
				}
			}
		}
		catch (IOException ex) {
			this.log.error("Cannot get first non-loopback address", ex);
		}

		if (result != null) {
			return result;
		}

		try {
			return InetAddress.getLocalHost();
		}
		catch (UnknownHostException e) {
			this.log.warn("Unable to retrieve localhost");
		}

		return null;
	}

sentinel能不能也参照nacos的获取ip逻辑优化下？

@ifrozenice Would you like to submit a PR to improve it?

我想从代码层面解决这个错误，但是目前以我的能力还还办不到。

越来越多的关于获取ip的问题。其实这里有一个成本较高但可用的fix可以尝试，那就是做一次当前节点到dashboard汇报节点的路由查找。路由查找成功后（网络能连通的情况下），本端ip即为正确ip。

路由查找的方式，除了获取路由表直接查找，还有一种比较近似的方法，就是尝试创建一下连接，从而拿到本端ip。

获取默认路由的方法（gateway）（直接使用数据报测试1.1.1.1的连通性）：

try(DatagramSocket s=new DatagramSocket())
{
    s.connect(InetAddress.getByAddress(new byte[]{1,1,1,1}), 0);
    return NetworkInterface.getByInetAddress(s.getLocalAddress()).getHardwareAddress();
}

更准确的，可以把目标ip更换为dashboard地址。