我想从URL发出请求,但遇到了问题:
val f: Future[Any] = actor1 ? SyncRequest(url)
f.onSuccess {
case feed: xml.Elem =>
val feedInfo = FeedInfo(
((feed \ "channel") \ "title").headOption.map(_.text).get,
((feed \ "channel") \ "description").headOption.map(_.text),
((feed \ "channel") \\ "item").map(item =>
FeedItem((item \ "title").headOption.map(_.text).get,
(item \ "link").headOption.map(_.text))
).toList
)
complete(feedInfo)
这是错误:
[error] value onSuccess is not a member of scala.concurrent.Future[Any]
[error] f.onSuccess {
[error] ^
[error] one error found
[error] (Compile / compileIncremental) Compilation failed
也许我必须使用类似OnComplete
的东西,而不是OnSuccess
?
1条答案
按热度按时间vohkndzv1#
onSuccess
方法在Scala 2.12中已弃用,在Scala 2.13中已删除@deprecated(“请改用
foreach
或onComplete
(请记住,它们接受全部函数而不是部分函数)",“2.12.0”)你最好的朋友现在是
onComplete