"extera_Ordering_json[id]"只是一个字符串，因此您需要迭代每个数组中的所有对象，并找到将该字符串作为name的数组，然后检查同一对象的value
这是一种Map和过滤器方法

var data = [
    [
        {"name":"formtype","value":"ordering"},          
        {"name":"extera_Ordering_json[id]","value":"1"}
   ],
   [
        {"name":"extera_Ordering_json[count]","value":"20"},               
        {"name":"coupon","value":""},
        {"name":"formtype","value":"ordering"}, 
        {"name":"extera_Ordering_json[id]","value":"2"}
   ],
   [
       {"name":"extera_Ordering_json[count]","value":"7"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"3"}
   ],
   [   {"name":"extera_Ordering_json[count]","value":"1"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"4"}
   ]
]
var searchVal = 1
data=data.map(function(arr){
   return arr.filter(function(o){
      return o.name !== "extera_Ordering_json[id]" || +o.value !== searchVal
   })
})

console.log(data)

您可以在JSON数组上使用splice方法来移除特定索引处的元素：

var ordering = JSON.stringify([
    [
        {"name":"formtype","value":"ordering"},          
        {"name":"extera_Ordering_json[id]","value":"1"}
   ],
   [
        {"name":"extera_Ordering_json[count]","value":"20"},               
        {"name":"coupon","value":""},
        {"name":"formtype","value":"ordering"}, 
        {"name":"extera_Ordering_json[id]","value":"2"}
   ],
   [
       {"name":"extera_Ordering_json[count]","value":"7"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"3"}
   ],
   [   {"name":"extera_Ordering_json[count]","value":"1"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"4"}
   ]
])

temp = JSON.parse(ordering);
temp.splice(3, 1)
ordering = JSON.stringify(temp);
console.log(ordering)

在您示例中，extera_Ordering_json[id]不是键，它是name的值
第一个

这应该可以完成您想要的任务：

var ordering = [
    [
        {"name":"formtype","value":"ordering"},          
        {"name":"extera_Ordering_json[id]","value":"1"}
    ],
    [
        {"name":"extera_Ordering_json[count]","value":"20"},               
        {"name":"coupon","value":""},
        {"name":"formtype","value":"ordering"}, 
        {"name":"extera_Ordering_json[id]","value":"2"}
    ],
    [
       {"name":"extera_Ordering_json[count]","value":"7"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"3"}
    ],
    [   
       {"name":"extera_Ordering_json[count]","value":"1"},
       {"name":"coupon","value":"1"},
       {"name":"formtype","value":"ordering"},
       {"name":"extera_Ordering_json[id]","value":"4"}
    ]
];
    var sVal = 4;
    var indexToRemove = false;
    ordering.forEach(function(element, index) {
       element.forEach(function(subelement) {
           if (subelement.name == "extera_Ordering_json[id]" 
              && parseInt(subelement.value) == sVal){
              indexToRemove = index;
           }
       });
    });

    if (false !== indexToRemove) {
        ordering.splice(indexToRemove, 1);
    }

您正在使用id而不是idx。请尝试以下操作

if(obj.Ordering_json[idx] != 4)

可以使用拼接方法

ordering = [ /*Array without json parsing*/ ];
var indexToDelete = 3;
ordering.splice( indexToDelete, 1); 
// 1 indicates only one element from array 
console.log(ordering);