使用Spring Integration,我需要将一个对象从外部API包转换为JSON,最后通过AmqpOutboundEndpoint发送它。
问题与该类的LocalDateTime属性有关:它们被序列化为整数数组[yyyy,mm,dd,HH,MM,ss]
,但我希望它们被转换为ISO 8601日期时间字符串。
我发现这个问题很常见,到目前为止,我已经将jackson-datatype-jsr 310添加到依赖项中,并设置了属性spring.jackson.serialization.write_data_as_timestamps: true
,但这没有帮助。
我需要一个可行方案的提示,拜托。
编辑:添加源代码(删除包和导入行)和pom.xml:
@Configuration
@EnableAutoConfiguration
@IntegrationComponentScan
public class Application {
public static void main(String[] args) throws InterruptedException {
ConfigurableApplicationContext ctx = SpringApplication.run(Application.class, args);
List<Data> source = Arrays.asList(new Data());
ctx.getBean(Demo.class).demo(source);
ctx.close();
}
@MessagingGateway
public interface Demo {
@Gateway(requestChannel = "upcase.input")
void demo(Collection<Data> source);
}
public static class Data {
public LocalDateTime getLocalDateTime() {
return LocalDateTime.now();
}
}
@Bean
public IntegrationFlow upcase() {
return f -> f
.split()
.log()
.transform(new ObjectToJsonTransformer())
.log()
.handle(m -> System.out.printf("%n%s%n%n", m.getPayload()));
}
}
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.7.5</version>
<relativePath /> <!-- lookup parent from repository -->
</parent>
<properties>
<spring.integration>5.5.15</spring.integration>
<java.version>11</java.version>
</properties>
<groupId>com.example</groupId>
<artifactId>spring-int</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>spring-int</name>
<description>Demo project for Spring Boot</description>
<dependencies>
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-integration</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
</project>
1条答案
按热度按时间mcvgt66p1#
我觉得你的期望正好相反。
LocalDateTimeSerializer
的逻辑如下:因此,对于
spring.jackson.serialization.write-dates-as-timestamps=true
(默认情况下),我们实际上将拥有一个LocalDateTime
属性数组。如果您谈论ISO 8601的格式,那么您需要做完全相反的事情:
spring.jackson.serialization.write-dates-as-timestamps=false
。此配置修改:以便能够采用正确自动配置的
ObjectMapper
。上述
LocalDateTimeSerializer
将通过以下方式进行LocalDateTime
化:使用此配置,输出如下所示: