你必须用像php这样的脚本语言来做这件事，至少我会这样做。我不是一个专业的开发人员，但我写了快速以下php脚本，得到以前的匹配出mysql数据库。你可以为下一场比赛做类似的事情。也许有一个更容易的方法来做到这一点，但这个脚本的工作...

<?php

/*get the current day*/
$day = date("d");

$previous = array();
$j = 0; /*this variable will say on which index we have to store the team name in the array previous*/
$k = 1; /*this variable will say how much days we have to count back*/

/*now we get the previous math out of the database be counting down the days and looking if there is a record*/
for($i=$day; $i>0; $i--) {
    $date = date("dmY", strtotime("-$k days"));

    $result = mysql_query("SELECT * FROM `football` WHERE `date`='$date'") or die (mysql_error());
    $num = mysql_num_rows($result);
    $fetch = mysql_fetch_array($result);

    if($num == 1) {
        $previous[$j] = $fetch["team"];
        $j++;
    }
    $k++;
}

echo $previous[0];

?>