在Java中创建XML有很多方法，下面的答案How to serialize and de-serialize objects using JAXB?提供了一个很好的演示，展示了一种似乎适合您的用例的常用方法。

以下是如何使用Apache HttpClient提交xml请求。

• 使用apache Velocity创建请求xml格式
• 使用Castor将响应流（respReader）转换为java对象

final String request = createXmlRequest(); // helper method to create the xml request
final HttpClient client = new HttpClient();
final PostMethod post = new PostMehod(url); // url - www.google.cm/someoperaion

post.setRequestHeader("Content-Language", "en-US");
post.setRequestEntity(new StringRequestEntity(request, "text/xml", "ISO-8859-1"));

final int returnCode = client.executeMethod(post);

final BufferedReader respReader = new BufferedReader(new InputStreamReader(post.getResponseBodyAsStream()));

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试着用这种方式...

public void postData() throws Exception {

 HttpClient client = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("https://www.xyz.com");

 List<NameValuePair> list = new ArrayList<NameValuePair>(1);

 list.add(new BasicNameValuePair("name","ABC");

 httppost.setEntity(new UrlEncodedFormEntity(list));

 HttpResponse r = client.execute(httppost);

}

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