我试图在phpMyAdmin中创建以下存储过程。但是,我一直得到这个错误:#1313 - RETURN is only allowed in a FUNCTION
CREATE PROCEDURE IS_POINT_IN_POLYGON()
BEGIN
DECLARE n INT DEFAULT 0;
DECLARE pX DECIMAL(19,16);
DECLARE pY DECIMAL(19,16);
DECLARE ls LINESTRING;
DECLARE poly1 POINT;
DECLARE poly1X DECIMAL(19,16);
DECLARE poly1Y DECIMAL(19,16);
DECLARE poly2 POINT;
DECLARE poly2X DECIMAL(19,16);
DECLARE poly2Y DECIMAL(19,16);
DECLARE i INT DEFAULT 0;
DECLARE result INT(1) DEFAULT 0;
SET pX = X(p);
SET pY = Y(p);
SET ls = ExteriorRing(poly);
SET poly2 = EndPoint(ls);
SET poly2X = X(poly2);
SET poly2Y = Y(poly2);
SET n = NumPoints(ls);
WHILE i<n DO
SET poly1 = PointN(ls, (i+1));
SET poly1X = X(poly1);
SET poly1Y = Y(poly1);
IF ( ( ( ( poly1X <= pX )
&& ( pX < poly2X ) ) || ( ( poly2X <= pX )
&& ( pX < poly1X ) ) )
&& ( pY > ( poly2Y - poly1Y ) * ( pX - poly1X ) / ( poly2X - poly1X ) + poly1Y ) ) THEN
SET result = !result;
END IF;
SET poly2X = poly1X;
SET poly2Y = poly1Y;
SET i = i + 1;
END WHILE;
RETURN result;
END//
字符串
如何解决这个问题呢?在SQL窗格中,我记得将SQL更改为//。
有什么建议吗?
2条答案
按热度按时间yvt65v4c1#
错误消息告诉你问题所在--你不能在
PROCEDURE
中使用RETURN
。创建一个FUNCTION
(CREATE FUNCTION
),它可以返回一个值。字符串
qqrboqgw2#
下面是同样的错误:
错误1313(42000):仅在FUNCTION中允许返回
当我用RETURN语句创建过程时,如下所示:
字符串
因此,我将
RETURN
语句替换为SELECT statement,如下所示,然后我可以创建过程而不会出错:型