powershell 从函数退出循环

arknldoa 于 3个月前发布在 Shell

关注(0)|答案(2)|浏览(70)

我想从一个函数中打破下面的循环，这个函数的调用方式如下所示。

Function test {
    $i++
    IF ($i -eq 10) {continue}
}

$Computers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($Computer in $Computers) {
    Test
    write-host "Fail"
}

字符串

powershell

来源：https://stackoverflow.com/questions/14670364/exit-loop-from-function

2条答案

按热度按时间

aiqt4smr1#

如果我跟踪你...

Function test {
    $args[0] -eq 10
}

$Computers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($Computer in $Computers) {
    if(Test $Computer) {break} else {$Computer}
}

字符串

赞(0）回复(0）举报 3个月前

ftf50wuq2#

我试过了，你真的可以。

Function Test ($i) {
    if ($i -eq 10) {continue}
    if ($i -eq 3)  {break}
}

$numbers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($number in $numbers) {
    Test $number
    write-host "$number"
}

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输出量：

型
因此，跳过了10，并在3时退出循环。
这样的编码是一种不好的做法，因为通常不期望函数中断循环。
除非函数的名称与循环有关，如“Exit-LoopOnFailure（）”

赞(0）回复(0）举报 3个月前

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powershell 从函数退出循环

2条答案

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