pycharm 从Google MAPS中提取评分和评论数量

7y4bm7vi  于 4个月前  发布在  PyCharm
关注(0)|答案(1)|浏览(58)

我仍然是乞丐,并试图提取评级(星数4.1为puple)和审查的数量为100个最好的花园在图卢兹城市。我已经取得了下面的代码,但是,我仍然无法提取所需的信息。
有人能帮帮忙吗,
提前谢谢你,伊利亚斯。

from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver import ActionChains
from selenium.webdriver.support.ui import WebDriverWait
import time

chrome_options = Options()
chrome_options.add_experimental_option("detach", True)

driver = webdriver.Chrome(options=chrome_options)
actionChains = ActionChains(driver)
wait = WebDriverWait(driver, 20)

def wait_for_element_location_to_be_stable(element):
    initial_location = element.location
    previous_location = initial_location
    start_time = time.time()
    while time.time() - start_time < 1:
        current_location = element.location
        if current_location != previous_location:
            previous_location = current_location
            start_time = time.time()
        time.sleep(0.4)

driver.get("https://www.google.com/")
driver.find_element(By.ID, "L2AGLb").click()

driver.get("https://www.google.com/maps")

# Wait for the page to load and display the search box
time.sleep(3)

# Input the search query for "jardins in toulouse" and press Enter
search_box = driver.find_element(By.ID, "searchboxinput")
search_box.send_keys("jardins in toulouse")
search_box.send_keys(Keys.RETURN)

# Wait for the search results to load
time.sleep(5)

# Updated XPath for the rating
rating_xpath = "/html/body/div[3]/div[8]/div[9]/div/div/div[1]/div[2]/div/div[1]/div/div/div[2]/div[1]"

# Get the elements based on the below XPath locator
results = driver.find_elements(By.XPATH, "//a[@class='hfpxzc']")

break_condition = False
focus_element = driver.find_element(By.ID, 'zero-input')
while not break_condition:
    temp = results[-1]
    actionChains.scroll_to_element(results[-1]).perform()
    actionChains.move_to_element(focus_element).click().perform()
    for i in range(3):
        actionChains.send_keys(Keys.ARROW_DOWN).perform()
        time.sleep(0.5)
    wait_for_element_location_to_be_stable(temp)

    results = wait.until(EC.presence_of_all_elements_located((By.XPATH, "//a[@class='hfpxzc']")))
    if results[-1] == temp:
        break_condition = True

# Loop through the results and print name and rating
for i, result in enumerate(results[:100], start=1):
    name = result.get_attribute('aria-label')
    rating_element = result.find_element(By.XPATH, rating_xpath)
    rating = rating_element.text if rating_element else "Rating not available"
    print(f"Result {i}: {name} - Rating: {rating}")

# Close the browser
driver.quit()

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我知道这里有非常熟练的人员可以帮助...

kxe2p93d

kxe2p93d1#

我很高兴你正在使用我的解决方案向下滚动谷歌Map。:)
在当前的情况下,您正在从DOM根使用绝对xpath获取评级,这将不起作用。该xpath仅从上下文根指向第一个评级元素。并且result变量本身没有您定义为评级xpath的元素(它不是上下文根)。
Rating放在card容器中。Card容器根是a元素的父元素。因此,您定义了..
构建定位器的第二步是找到评级元素。它具有唯一的类MW4etd
因此,来自result元素的评级定位器是..//*[@class='MW4etd']
要切断非评级结果,您可以从result获取元素列表并检查它是否大于0。

for i, result in enumerate(results[:100], start=1):
    name = result.get_attribute('aria-label')
    ratings = result.find_elements(By.XPATH, "..//*[@class='MW4etd']")
    rating = ratings[0].text if len(ratings) > 0 else "Rating not available"
    print(f"Result {i}: {name} - Rating: {rating}")

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