org.hibernate.mapping.Property.resolveServiceRegistry()方法的使用及代码示例

x33g5p2x  于2022-01-26 转载在 其他  
字(1.5k)|赞(0)|评价(0)|浏览(89)

本文整理了Java中org.hibernate.mapping.Property.resolveServiceRegistry()方法的一些代码示例,展示了Property.resolveServiceRegistry()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Property.resolveServiceRegistry()方法的具体详情如下:
包路径:org.hibernate.mapping.Property
类名称:Property
方法名:resolveServiceRegistry

Property.resolveServiceRegistry介绍

暂无

代码示例

代码示例来源:origin: hibernate/hibernate-orm

public PropertyAccessStrategy getPropertyAccessStrategy(Class clazz) throws MappingException {
  String accessName = getPropertyAccessorName();
  if ( accessName == null ) {
    if ( clazz == null || java.util.Map.class.equals( clazz ) ) {
      accessName = "map";
    }
    else {
      accessName = "property";
    }
  }
  final EntityMode entityMode = clazz == null || java.util.Map.class.equals( clazz )
      ? EntityMode.MAP
      : EntityMode.POJO;
  return resolveServiceRegistry().getService( PropertyAccessStrategyResolver.class ).resolvePropertyAccessStrategy(
      clazz,
      accessName,
      entityMode
  );
}

代码示例来源:origin: org.hibernate.orm/hibernate-core

public PropertyAccessStrategy getPropertyAccessStrategy(Class clazz) throws MappingException {
  String accessName = getPropertyAccessorName();
  if ( accessName == null ) {
    if ( clazz == null || java.util.Map.class.equals( clazz ) ) {
      accessName = "map";
    }
    else {
      accessName = "property";
    }
  }
  final EntityMode entityMode = clazz == null || java.util.Map.class.equals( clazz )
      ? EntityMode.MAP
      : EntityMode.POJO;
  return resolveServiceRegistry().getService( PropertyAccessStrategyResolver.class ).resolvePropertyAccessStrategy(
      clazz,
      accessName,
      entityMode
  );
}

相关文章

微信公众号

最新文章

更多