本文整理了Java中org.hibernate.engine.spi.SessionFactoryImplementor.getName()方法的一些代码示例，展示了SessionFactoryImplementor.getName()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。SessionFactoryImplementor.getName()方法的具体详情如下：
包路径：org.hibernate.engine.spi.SessionFactoryImplementor
类名称：SessionFactoryImplementor
方法名：getName

SessionFactoryImplementor.getName介绍

[英]Access to the name (if one) assigned to the SessionFactory
[中]

代码示例

代码示例来源：origin: hibernate/hibernate-orm

@Override
public String getName() {
  return delegate.getName();
}

代码示例来源：origin: org.hibernate.orm/hibernate-core

@Override
public String getName() {
  return delegate.getName();
}

代码示例来源：origin: hibernate/hibernate-search

@Override
public synchronized void register(SessionFactoryImplementor sessionFactory) {
  sessionFactories.add( sessionFactory );
  Object persistenceUnitName = sessionFactory.getProperties().get( AvailableSettings.PERSISTENCE_UNIT_NAME );
  if ( persistenceUnitName instanceof String ) {
    sessionFactoriesByPUName.put( (String) persistenceUnitName, sessionFactory );
  }
  String name = sessionFactory.getName();
  if ( name != null ) {
    sessionFactoriesByName.put( name, sessionFactory );
  }
}

代码示例来源：origin: hibernate/hibernate-ogm

public OgmSessionFactoryImpl(SessionFactoryImplementor delegate) {
  super( delegate );
  try {
    uuid = (String) UUID_GENERATOR.generate( null, null );
  }
  catch (Exception e) {
    throw new AssertionFailure( "Could not generate UUID" );
  }
  SessionFactoryRegistry.INSTANCE.addSessionFactory(
      uuid,
      delegate.getName(),
      delegate.getSessionFactoryOptions().isSessionFactoryNameAlsoJndiName(),
      this,
      delegate.getServiceRegistry().getService( JndiService.class )
  );
}