本文整理了Java中com.google.javascript.jscomp.SourceFile.getLine()
方法的一些代码示例,展示了SourceFile.getLine()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。SourceFile.getLine()
方法的具体详情如下:
包路径:com.google.javascript.jscomp.SourceFile
类名称:SourceFile
方法名:getLine
[英]Gets the source line for the indicated line number.
[中]获取指定行号的源行。
代码示例来源:origin: org.apache.royale.compiler/compiler-externc
protected String getSourceCode(StaticSourceFile file, int line)
{
if (file instanceof SourceFile)
{
String code = ((SourceFile)file).getLine(line);
return code;
}
return "no source line found";
}
代码示例来源:origin: org.apache.flex.flexjs.compiler/compiler-jx
protected String getSourceCode(StaticSourceFile file, int line)
{
if (file instanceof SourceFile)
{
String code = ((SourceFile)file).getLine(line);
return code;
}
return "no source line found";
}
代码示例来源:origin: org.apache.flex.flexjs.compiler/compiler-jx
@Override
public String getLine(int lineNumber) {
return super.getLine(lineNumber);
}
代码示例来源:origin: apache/royale-compiler
protected String getSourceCode(StaticSourceFile file, int line)
{
if (file instanceof SourceFile)
{
String code = ((SourceFile)file).getLine(line);
return code;
}
return "no source line found";
}
代码示例来源:origin: apache/royale-compiler
@Override
public String getLine(int lineNumber) {
return super.getLine(lineNumber);
}
代码示例来源:origin: com.google.javascript/closure-compiler
@Override
public String getSourceLine(String sourceName, int lineNumber) {
if (lineNumber < 1) {
return null;
}
SourceFile input = getSourceFileByName(sourceName);
if (input != null) {
return input.getLine(lineNumber);
}
return null;
}
代码示例来源:origin: org.scala-js/closure-compiler-java-6
@Override
public String getSourceLine(String sourceName, int lineNumber) {
if (lineNumber < 1) {
return null;
}
SourceFile input = getSourceFileByName(sourceName);
if (input != null) {
return input.getLine(lineNumber);
}
return null;
}
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