本文整理了Java中gov.sandia.cognition.math.matrix.Vector.dot()方法的一些代码示例，展示了Vector.dot()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Vector.dot()方法的具体详情如下：
包路径：gov.sandia.cognition.math.matrix.Vector
类名称：Vector
方法名：dot

Vector.dot介绍

[英]Element-wise division of this by other. Note that if other has zero elements the result will contain NaNvalues.
[中]在元素方面，它被其他元素分割。请注意，如果其他元素为零，则结果将包含值。

代码示例

代码示例来源：origin: algorithmfoundry/Foundry

result += input.dot(this.weights);

代码示例来源：origin: algorithmfoundry/Foundry

final double sumOfSquares = derivative.norm2Squared();
final double newWeight = sumOfSquares == 0.0 ? 0.0 :
  (oldWeight * sumOfSquares + derivative.dot(errors))
  / (sumOfSquares + this.weightRegularization);
weights.set(j, newWeight);
    this.dataList.get(i).getInput().dot(factorRow));

代码示例来源：origin: gov.sandia.foundry/gov-sandia-cognition-learning-core

final double sumOfSquares = derivative.norm2Squared();
final double newWeight = sumOfSquares == 0.0 ? 0.0 :
  (oldWeight * sumOfSquares + derivative.dot(errors))
  / (sumOfSquares + this.weightRegularization);
weights.set(j, newWeight);
    this.dataList.get(i).getInput().dot(factorRow));

代码示例来源：origin: gov.sandia.foundry/gov-sandia-cognition-learning-core

result += input.dot(this.weights);

代码示例来源：origin: algorithmfoundry/Foundry

final double sumOfSquares = derivative.norm2Squared();
final double newWeight = sumOfSquares == 0.0 ? 0.0 :
  (oldWeight * sumOfSquares + derivative.dot(errors))
  / (sumOfSquares + this.weightRegularization);
weights.set(j, newWeight);
    this.dataList.get(i).getInput().dot(factorRow));

代码示例来源：origin: algorithmfoundry/Foundry

result += input.dot(this.weights);