本文整理了Java中org.apache.catalina.WebResourceRoot.listWebAppPaths()方法的一些代码示例，展示了WebResourceRoot.listWebAppPaths()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。WebResourceRoot.listWebAppPaths()方法的具体详情如下：
包路径：org.apache.catalina.WebResourceRoot
类名称：WebResourceRoot
方法名：listWebAppPaths

WebResourceRoot.listWebAppPaths介绍

[英]Obtain the Set of the web applications pathnames of all of the files and directories located in the specified directory. Paths representing directories will end with a '/' character.
[中]获取位于指定目录中的所有文件和目录的web应用程序路径名集。代表目录的路径将以“/”字符结尾。

代码示例

代码示例来源：origin: org.apache.tomee/tomee-catalina

@Override
public Set<String> listWebAppPaths(final String path) {
  return delegate.listWebAppPaths(path);
}

代码示例来源：origin: org.apache.tomcat/tomcat-catalina

@Override
public Set<String> getResourcePaths(String path) {
  // Validate the path argument
  if (path == null) {
    return null;
  }
  if (!path.startsWith("/")) {
    throw new IllegalArgumentException
      (sm.getString("applicationContext.resourcePaths.iae", path));
  }
  WebResourceRoot resources = context.getResources();
  if (resources != null) {
    return resources.listWebAppPaths(path);
  }
  return null;
}

代码示例来源：origin: org.ops4j.pax.tipi/org.ops4j.pax.tipi.tomcat-embed-core

@Override
public Set<String> getResourcePaths(String path) {
  // Validate the path argument
  if (path == null) {
    return null;
  }
  if (!path.startsWith("/")) {
    throw new IllegalArgumentException
      (sm.getString("applicationContext.resourcePaths.iae", path));
  }
  WebResourceRoot resources = context.getResources();
  if (resources != null) {
    return resources.listWebAppPaths(path);
  }
  return null;
}

代码示例来源：origin: codefollower/Tomcat-Research

/**
 * Return a Set containing the resource paths of resources member of the
 * specified collection. Each path will be a String starting with
 * a "/" character. Paths representing directories will end with a "/"
 * character.
 *
 * @param path Collection path
 */
@Override
public Set<String> getResourcePaths(String path) {
  // Validate the path argument
  if (path == null) {
    return null;
  }
  if (!path.startsWith("/")) {
    throw new IllegalArgumentException
      (sm.getString("applicationContext.resourcePaths.iae", path));
  }
  WebResourceRoot resources = context.getResources();
  if (resources != null) {
    return resources.listWebAppPaths(path);
  }
  return null;
}