okio.Buffer.readInt()方法的使用及代码示例

x33g5p2x  于2022-01-16 转载在 其他  
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本文整理了Java中okio.Buffer.readInt()方法的一些代码示例,展示了Buffer.readInt()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Buffer.readInt()方法的具体详情如下:
包路径:okio.Buffer
类名称:Buffer
方法名:readInt

Buffer.readInt介绍

暂无

代码示例

代码示例来源:origin: square/okhttp

final long ttl = buf.readInt() & 0xffffffffL; // ttl
final int length = buf.readShort() & 0xffff;

代码示例来源:origin: huxq17/tractor

@Override public int readInt() throws IOException {
 require(4);
 return buffer.readInt();
}

代码示例来源:origin: huxq17/tractor

@Override public int readIntLe() {
 return Util.reverseBytesInt(readInt());
}

代码示例来源:origin: huxq17/tractor

@Override public long readLong() {
 if (size < 8) throw new IllegalStateException("size < 8: " + size);
 Segment segment = head;
 int pos = segment.pos;
 int limit = segment.limit;
 // If the long is split across multiple segments, delegate to readInt().
 if (limit - pos < 8) {
  return (readInt() & 0xffffffffL) << 32
    |  (readInt() & 0xffffffffL);
 }
 byte[] data = segment.data;
 long v = (data[pos++] & 0xffL) << 56
   |    (data[pos++] & 0xffL) << 48
   |    (data[pos++] & 0xffL) << 40
   |    (data[pos++] & 0xffL) << 32
   |    (data[pos++] & 0xffL) << 24
   |    (data[pos++] & 0xffL) << 16
   |    (data[pos++] & 0xffL) <<  8
   |    (data[pos++] & 0xffL);
 size -= 8;
 if (pos == limit) {
  head = segment.pop();
  SegmentPool.recycle(segment);
 } else {
  segment.pos = pos;
 }
 return v;
}

代码示例来源:origin: com.squareup.okhttp3/okhttp-dnsoverhttps

final long ttl = buf.readInt() & 0xffffffffL; // ttl
final int length = buf.readShort() & 0xffff;

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