本文整理了Java中java.lang.Math.pow()方法的一些代码示例，展示了Math.pow()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Math.pow()方法的具体详情如下：
包路径：java.lang.Math
类名称：Math
方法名：pow

Math.pow介绍

[英]Returns the closest double approximation of the result of raising x to the power of y.

Special cases:

• pow((anything), +0.0) = 1.0
• pow((anything), -0.0) = 1.0
• pow(x, 1.0) = x
• pow((anything), NaN) = NaN
• pow(NaN, (anything except 0)) = NaN
• pow(+/-(|x| > 1), +infinity) = +infinity
• pow(+/-(|x| > 1), -infinity) = +0.0
• pow(+/-(|x| < 1), +infinity) = +0.0
• pow(+/-(|x| < 1), -infinity) = +infinity
• pow(+/-1.0 , +infinity) = NaN
• pow(+/-1.0 , -infinity) = NaN
• pow(+0.0, (+anything except 0, NaN)) = +0.0
• pow(-0.0, (+anything except 0, NaN, odd integer)) = +0.0
• pow(+0.0, (-anything except 0, NaN)) = +infinity
• pow(-0.0, (-anything except 0, NAN, odd integer)) = +infinity
• pow(-0.0, (odd integer)) = -pow( +0 , (odd integer) )
• pow(+infinity, (+anything except 0, NaN)) = +infinity
• pow(+infinity, (-anything except 0, NaN)) = +0.0
• pow(-infinity, (anything)) = -pow(0, (-anything))
• pow((-anything), (integer)) = pow(-1,(integer))*pow(+anything,integer)
• pow((-anything except 0 and inf), (non-integer)) = NAN
  [中]返回将x提高到y的幂的结果的最接近的双近似值。
  特殊情况：
  *功率（（任何），+0.0）=1.0
  *功率（（任何事物），-0.0）=1.0
  *功率（x，1.0）=x
  *战俘（（任何事），楠）=楠
  *pow（NaN，（除0以外的任何值））=NaN
  *功率（+/-（|x |>1），+infinity）=+infinity
  *功率（+/-（|x |>1），-无穷大）=+0.0
  *功率（+/-（|x |<1），+无穷大）=+0.0
  *功率（+/-（|x |<1），-无穷大）=+无穷大
  *功率（+/-1.0，+无穷大）=NaN
  *功率（+/-1.0，-无穷大）=NaN
  *战力（+0.0，（+除0以外的任何东西，NaN））=+0.0
  *功率（-0.0，（+除0以外的任何值，NaN，奇整数））=+0.0
  *功率（+0.0，（-除0，NaN外的任何东西））=+无穷大
  *pow（-0.0，（-除0以外的任何值，NAN，奇整数））=+无穷大
  *功率（-0.0，（奇数整数））=-pow（+0，（奇数整数））
  *功率（+无穷大，（+除0以外的任何事物，NaN））=+无穷大
  *功率（+无穷大，（-除了0，NaN以外的任何东西））=+0.0
  *pow（-无穷大，（任何事物））=-pow（0，（-任何事物））
  *pow（（-anything），（integer））=pow（-1，（integer））*pow（+anything，integer）
  *pow（（-除0和inf之外的任何值），（非整数））=NAN

代码示例

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a <= 0.5f) return (float)Math.pow(a * 2, power) / 2;
    return (float)Math.pow((a - 1) * 2, power) / (power % 2 == 0 ? -2 : 2) + 1;
  }
}

代码示例来源：origin: libgdx/libgdx

public int reset () {
  low = min;
  high = max;
  current = (low + high) >>> 1;
  if (pot) return (int)Math.pow(2, current);
  if (mod4) return current % 4 == 0 ? current : current + 4 - (current % 4);
  return current;
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a <= 0.5f) return ((float)Math.pow(value, power * (a * 2 - 1)) - min) * scale / 2;
    return (2 - ((float)Math.pow(value, -power * (a * 2 - 1)) - min) * scale) / 2;
  }
};

代码示例来源：origin: libgdx/libgdx

public Exp (float value, float power) {
  this.value = value;
  this.power = power;
  min = (float)Math.pow(value, -power);
  scale = 1 / (1 - min);
}

代码示例来源：origin: libgdx/libgdx

public Exp (float value, float power) {
  this.value = value;
  this.power = power;
  min = (float)Math.pow(value, -power);
  scale = 1 / (1 - min);
}

代码示例来源：origin: libgdx/libgdx

public int reset () {
  low = min;
  high = max;
  current = (low + high) >>> 1;
  if (pot) return (int)Math.pow(2, current);
  if (mod4) return current % 4 == 0 ? current : current + 4 - (current % 4);
  return current;
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a <= 0.5f) return ((float)Math.pow(value, power * (a * 2 - 1)) - min) * scale / 2;
    return (2 - ((float)Math.pow(value, -power * (a * 2 - 1)) - min) * scale) / 2;
  }
};

代码示例来源：origin: stackoverflow.com

public static String humanReadableByteCount(long bytes, boolean si) {
  int unit = si ? 1000 : 1024;
  if (bytes < unit) return bytes + " B";
  int exp = (int) (Math.log(bytes) / Math.log(unit));
  String pre = (si ? "kMGTPE" : "KMGTPE").charAt(exp-1) + (si ? "" : "i");
  return String.format("%.1f %sB", bytes / Math.pow(unit, exp), pre);
}

代码示例来源：origin: stackoverflow.com

public static double round(double value, int places) {
  if (places < 0) throw new IllegalArgumentException();

  long factor = (long) Math.pow(10, places);
  value = value * factor;
  long tmp = Math.round(value);
  return (double) tmp / factor;
}

代码示例来源：origin: apache/incubator-dubbo

private static int parseInt(String version) {
  int v = 0;
  String[] vArr = version.split("\\.");
  int len = vArr.length;
  for (int i = 0; i < len; i++) {
    v += Integer.parseInt(getDigital(vArr[i])) * Math.pow(10, (len - i - 1) * 2);
  }
  return v;
}

代码示例来源：origin: apache/incubator-dubbo

private static int parseInt(String version) {
  int v = 0;
  String[] vArr = version.split("\\.");
  int len = vArr.length;
  for (int i = 0; i < len; i++) {
    v += Integer.parseInt(getDigital(vArr[i])) * Math.pow(10, (len - i - 1) * 2);
  }
  return v;
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a == 0) return 0;
    a = 1 - a;
    return (1 - (float)Math.pow(value, power * (a - 1)) * MathUtils.sin(a * bounces) * scale);
  }
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a <= 0.5f) {
      a *= 2;
      return (float)Math.pow(value, power * (a - 1)) * MathUtils.sin(a * bounces) * scale / 2;
    }
    a = 1 - a;
    a *= 2;
    return 1 - (float)Math.pow(value, power * (a - 1)) * MathUtils.sin((a) * bounces) * scale / 2;
  }
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a >= 0.99) return 1;
    return (float)Math.pow(value, power * (a - 1)) * MathUtils.sin(a * bounces) * scale;
  }
}

代码示例来源：origin: alibaba/druid

public static Histogram makeHistogram(int rangeCount) {
  long[] rangeValues = new long[rangeCount];
  for (int i = 0; i < rangeValues.length; ++i) {
    rangeValues[i] = (long) Math.pow(10, i);
  }
  return new Histogram(rangeValues);
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a == 0) return 0;
    a = 1 - a;
    return (1 - (float)Math.pow(value, power * (a - 1)) * MathUtils.sin(a * bounces) * scale);
  }
}

代码示例来源：origin: libgdx/libgdx

public float apply (float a) {
    if (a <= 0.5f) {
      a *= 2;
      return (float)Math.pow(value, power * (a - 1)) * MathUtils.sin(a * bounces) * scale / 2;
    }
    a = 1 - a;
    a *= 2;
    return 1 - (float)Math.pow(value, power * (a - 1)) * MathUtils.sin((a) * bounces) * scale / 2;
  }
}

代码示例来源：origin: google/guava

/**
 * Returns the probability that {@linkplain #mightContain(Object)} will erroneously return {@code
 * true} for an object that has not actually been put in the {@code BloomFilter}.
 *
 * <p>Ideally, this number should be close to the {@code fpp} parameter passed in {@linkplain
 * #create(Funnel, int, double)}, or smaller. If it is significantly higher, it is usually the
 * case that too many elements (more than expected) have been put in the {@code BloomFilter},
 * degenerating it.
 *
 * @since 14.0 (since 11.0 as expectedFalsePositiveProbability())
 */
public double expectedFpp() {
 // You down with FPP? (Yeah you know me!) Who's down with FPP? (Every last homie!)
 return Math.pow((double) bits.bitCount() / bitSize(), numHashFunctions);
}

代码示例来源：origin: spring-projects/spring-framework

@Test
public void SPR9486_floatPowerFloat() {
  Number expectedResult = Math.pow(10.21f, -10.2f);
  ExpressionParser parser = new SpelExpressionParser();
  StandardEvaluationContext context = new StandardEvaluationContext();
  Expression expression = parser.parseExpression("10.21f ^ -10.2f");
  Number result = expression.getValue(context, null, Number.class);
  assertEquals(expectedResult, result);
}

代码示例来源：origin: spring-projects/spring-framework

@Test
public void SPR9486_floatPowerDouble() {
  Number expectedResult = Math.pow(10.21f, 10.2);
  ExpressionParser parser = new SpelExpressionParser();
  StandardEvaluationContext context = new StandardEvaluationContext();
  Expression expression = parser.parseExpression("10.21f ^ 10.2");
  Number result = expression.getValue(context, null, Number.class);
  assertEquals(expectedResult, result);
}