本文整理了Java中org.w3c.dom.Document.getNextSibling()
方法的一些代码示例,展示了Document.getNextSibling()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Document.getNextSibling()
方法的具体详情如下:
包路径:org.w3c.dom.Document
类名称:Document
方法名:getNextSibling
暂无
代码示例来源:origin: org.swinglabs/swingx-ws
/**
* @inheritDoc
*/
public Node getNextSibling() {
return dom.getNextSibling();
}
代码示例来源:origin: org.opensingular/form-core
@Override
public Node getNextSibling() {
return original_.getNextSibling();
}
代码示例来源:origin: axis/axis
public Node getNextSibling(){
return document.getNextSibling();
}
代码示例来源:origin: org.jboss.ws.native/jbossws-native-core
public Node getNextSibling()
{
return this.doc.getNextSibling();
}
代码示例来源:origin: org.opensingular/singular-commons
@Override
public Node getNextSibling() {
return original_.getNextSibling();
}
代码示例来源:origin: org.apache.axis/axis
public Node getNextSibling(){
return document.getNextSibling();
}
代码示例来源:origin: org.apache.axis/com.springsource.org.apache.axis
public Node getNextSibling(){
return document.getNextSibling();
}
代码示例来源:origin: org.apache.axis2/axis2-saaj
/**
* The node immediately following this node. If there is no such node, this returns
* <code>null</code>.
*/
public Node getNextSibling() {
return toSAAJNode(document.getNextSibling());
}
代码示例来源:origin: apache/axis2-java
/**
* The node immediately following this node. If there is no such node, this returns
* <code>null</code>.
*/
public Node getNextSibling() {
return toSAAJNode(document.getNextSibling());
}
代码示例来源:origin: apache/servicemix-bundles
@Override
public Node getNextSibling() {
return findIfPresent(document.getNextSibling());
}
代码示例来源:origin: org.apache.ws.commons.axiom/dom-testsuite
protected void runTest() throws Throwable {
Document doc = dbf.newDocumentBuilder().newDocument();
Element elem = doc.createElement("test");
doc.appendChild(elem);
Node node = doc.getNextSibling();
assertNull("Document's next sibling has to be null", node);
Node node2 = doc.getPreviousSibling();
assertNull("Document's previous sibling has to be null", node2);
Node node3 = doc.getParentNode();
assertNull("Document's parent has to be null", node3);
}
}
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