org.w3c.dom.Document.getNextSibling()方法的使用及代码示例

x33g5p2x  于2022-01-17 转载在 其他  
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本文整理了Java中org.w3c.dom.Document.getNextSibling()方法的一些代码示例,展示了Document.getNextSibling()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Document.getNextSibling()方法的具体详情如下:
包路径:org.w3c.dom.Document
类名称:Document
方法名:getNextSibling

Document.getNextSibling介绍

暂无

代码示例

代码示例来源:origin: org.swinglabs/swingx-ws

/**
 * @inheritDoc
 */
public Node getNextSibling() {
  return dom.getNextSibling();
}

代码示例来源:origin: org.opensingular/form-core

@Override
public Node getNextSibling() {
  return original_.getNextSibling();
}

代码示例来源:origin: axis/axis

public Node getNextSibling(){
  return document.getNextSibling();
}

代码示例来源:origin: org.jboss.ws.native/jbossws-native-core

public Node getNextSibling()
{
 return this.doc.getNextSibling();
}

代码示例来源:origin: org.opensingular/singular-commons

@Override
public Node getNextSibling() {
  return original_.getNextSibling();
}

代码示例来源:origin: org.apache.axis/axis

public Node getNextSibling(){
  return document.getNextSibling();
}

代码示例来源:origin: org.apache.axis/com.springsource.org.apache.axis

public Node getNextSibling(){
  return document.getNextSibling();
}

代码示例来源:origin: org.apache.axis2/axis2-saaj

/**
 * The node immediately following this node. If there is no such node, this returns
 * <code>null</code>.
 */
public Node getNextSibling() {
  return toSAAJNode(document.getNextSibling());
}

代码示例来源:origin: apache/axis2-java

/**
 * The node immediately following this node. If there is no such node, this returns
 * <code>null</code>.
 */
public Node getNextSibling() {
  return toSAAJNode(document.getNextSibling());
}

代码示例来源:origin: apache/servicemix-bundles

@Override
public Node getNextSibling() {
  return findIfPresent(document.getNextSibling());
}

代码示例来源:origin: org.apache.ws.commons.axiom/dom-testsuite

protected void runTest() throws Throwable {
    Document doc = dbf.newDocumentBuilder().newDocument();
    Element elem = doc.createElement("test");
    doc.appendChild(elem);

    Node node = doc.getNextSibling();
    assertNull("Document's next sibling has to be null", node);
    Node node2 = doc.getPreviousSibling();
    assertNull("Document's previous sibling has to be null", node2);
    Node node3 = doc.getParentNode();
    assertNull("Document's parent has to be null", node3);
  }
}

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Document类方法