org.hibernate.cfg.Environment.jvmHasJDK14Timestamp()方法的使用及代码示例

x33g5p2x  于2022-01-19 转载在 其他  
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本文整理了Java中org.hibernate.cfg.Environment.jvmHasJDK14Timestamp()方法的一些代码示例,展示了Environment.jvmHasJDK14Timestamp()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Environment.jvmHasJDK14Timestamp()方法的具体详情如下:
包路径:org.hibernate.cfg.Environment
类名称:Environment
方法名:jvmHasJDK14Timestamp

Environment.jvmHasJDK14Timestamp介绍

[英]Does this JVM handle Timestamp in the JDK 1.4 compliant way?
[中]这个JVM是否以JDK1.4兼容的方式处理时间戳?

代码示例

代码示例来源:origin: jboss.jboss-embeddable-ejb3/hibernate-all

public boolean isEqual(Object x, Object y) {
  if (x==y) return true;
  if (x==null || y==null) return false;
  long xTime = ( (java.util.Date) x ).getTime();
  long yTime = ( (java.util.Date) y ).getTime();
  boolean xts = x instanceof Timestamp;
  boolean yts = y instanceof Timestamp;
  int xNanos = xts ? ( (Timestamp) x ).getNanos() : 0;
  int yNanos = yts ? ( (Timestamp) y ).getNanos() : 0;
  if ( !Environment.jvmHasJDK14Timestamp() ) {
    xTime += xNanos / 1000000;
    yTime += yNanos / 1000000;
  }
  if ( xTime!=yTime ) return false;
  if (xts && yts) {
    // both are Timestamps
    int xn = xNanos % 1000000;
    int yn = yNanos % 1000000;
    return xn==yn;
  }
  else {
    // at least one is a plain old Date
    return true;
  }
}

代码示例来源:origin: hibernate/hibernate

public boolean isEqual(Object x, Object y) {
  if (x==y) return true;
  if (x==null || y==null) return false;
  long xTime = ( (java.util.Date) x ).getTime();
  long yTime = ( (java.util.Date) y ).getTime();
  boolean xts = x instanceof Timestamp;
  boolean yts = y instanceof Timestamp;
  int xNanos = xts ? ( (Timestamp) x ).getNanos() : 0;
  int yNanos = yts ? ( (Timestamp) y ).getNanos() : 0;
  if ( !Environment.jvmHasJDK14Timestamp() ) {
    xTime += xNanos / 1000000;
    yTime += yNanos / 1000000;
  }
  if ( xTime!=yTime ) return false;
  if (xts && yts) {
    // both are Timestamps
    int xn = xNanos % 1000000;
    int yn = yNanos % 1000000;
    return xn==yn;
  }
  else {
    // at least one is a plain old Date
    return true;
  }
}

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