本文整理了Java中com.amazonaws.http.JsonErrorResponseHandler.unmarshallException()方法的一些代码示例，展示了JsonErrorResponseHandler.unmarshallException()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。JsonErrorResponseHandler.unmarshallException()方法的具体详情如下：
包路径：com.amazonaws.http.JsonErrorResponseHandler
类名称：JsonErrorResponseHandler
方法名：unmarshallException

JsonErrorResponseHandler.unmarshallException介绍

暂无

代码示例

代码示例来源：origin: aws/aws-sdk-java

/**
 * Create an AmazonServiceException using the chain of unmarshallers. This method will never
 * return null, it will always return a valid AmazonServiceException
 *
 * @param errorCode
 *            Error code to find an appropriate unmarshaller
 * @param jsonContent
 *            JsonContent of HTTP response
 * @return AmazonServiceException
 */
private AmazonServiceException createException(String errorCode, JsonContent jsonContent) {
  AmazonServiceException ase = unmarshallException(errorCode, jsonContent);
  if (ase == null) {
    ase = new AmazonServiceException(
        "Unable to unmarshall exception response with the unmarshallers provided");
  }
  return ase;
}

代码示例来源：origin: com.amazonaws/aws-java-sdk-core

/**
 * Create an AmazonServiceException using the chain of unmarshallers. This method will never
 * return null, it will always return a valid AmazonServiceException
 *
 * @param errorCode
 *            Error code to find an appropriate unmarshaller
 * @param jsonContent
 *            JsonContent of HTTP response
 * @return AmazonServiceException
 */
private AmazonServiceException createException(String errorCode, JsonContent jsonContent) {
  AmazonServiceException ase = unmarshallException(errorCode, jsonContent);
  if (ase == null) {
    ase = new AmazonServiceException(
        "Unable to unmarshall exception response with the unmarshallers provided");
  }
  return ase;
}

代码示例来源：origin: Nextdoor/bender

/**
 * Create an AmazonServiceException using the chain of unmarshallers. This method will never
 * return null, it will always return a valid AmazonServiceException
 *
 * @param errorCode
 *            Error code to find an appropriate unmarshaller
 * @param jsonContent
 *            JsonContent of HTTP response
 * @return AmazonServiceException
 */
private AmazonServiceException createException(String errorCode, JsonContent jsonContent) {
  AmazonServiceException ase = unmarshallException(errorCode, jsonContent);
  if (ase == null) {
    ase = new AmazonServiceException(
        "Unable to unmarshall exception response with the unmarshallers provided");
  }
  return ase;
}