javax.jms.QueueSession.unsubscribe()方法的使用及代码示例

x33g5p2x  于2022-01-28 转载在 其他  
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本文整理了Java中javax.jms.QueueSession.unsubscribe方法的一些代码示例,展示了QueueSession.unsubscribe的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。QueueSession.unsubscribe方法的具体详情如下:
包路径:javax.jms.QueueSession
类名称:QueueSession
方法名:unsubscribe

QueueSession.unsubscribe介绍

暂无

代码示例

代码示例来源:origin: objectweb-joramtests/joramtests

/**
* Test that a call to <code>unsubscribe()</code> method 
* on a <code>QueueSession</code> throws a 
* <code>javax.jms.IllegalStateException</code>.
* (see JMS 1.1 specs, table 4-1).
* 
* @since JMS 1.1
*/
public void testUnsubscribeOnQueueSession()
{
 try
 {
   queueSession.unsubscribe("subscriptionName");
   fail("Should throw a javax.jms.IllegalStateException");
 }
 catch (javax.jms.IllegalStateException e)
 {
 }
 catch (JMSException e)
 {
   fail("Should throw a javax.jms.IllegalStateException, not a " + e);
 }
}

代码示例来源:origin: apache/activemq-artemis

/**
* Test that a call to <code>unsubscribe()</code> method
* on a <code>QueueSession</code> throws a
* <code>javax.jms.IllegalStateException</code>.
* (see JMS 1.1 specs, table 4-1).
*
* @since JMS 1.1
*/
@Test
public void testUnsubscribeOnQueueSession() {
 try {
   queueSession.unsubscribe("subscriptionName");
   Assert.fail("Should throw a javax.jms.IllegalStateException");
 } catch (javax.jms.IllegalStateException e) {
 } catch (JMSException e) {
   Assert.fail("Should throw a javax.jms.IllegalStateException, not a " + e);
 }
}

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