本文整理了Java中org.apache.felix.resolver.Util.isMultiple()方法的一些代码示例，展示了Util.isMultiple()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Util.isMultiple()方法的具体详情如下：
包路径：org.apache.felix.resolver.Util
类名称：Util
方法名：isMultiple

Util.isMultiple介绍

暂无

代码示例

代码示例来源：origin: apache/felix

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: at.bestsolution.efxclipse.eclipse/org.eclipse.osgi

public void permutate(Requirement req, List<Candidates> permutations)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    permutations.add(perm);
  }
}

代码示例来源：origin: forge/roaster

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: biz.aQute.bnd/biz.aQute.bnd

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: com.github.veithen.cosmos/cosmos-equinox

public void permutate(Requirement req, List<Candidates> permutations)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    permutations.add(perm);
  }
}

代码示例来源：origin: org.eclipse.scout.sdk.deps/org.eclipse.osgi

public void permutate(Requirement req, List<Candidates> permutations)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    permutations.add(perm);
  }
}

代码示例来源：origin: org.eclipse.tycho/org.eclipse.osgi

private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
{
  // Sanity check for multiple.
  if (Util.isMultiple(req))
  {
    return false;
  }
  // If we've already permutated this requirement in another
  // uses constraint, don't permutate it again just continue
  // with the next uses constraint.
  if (mutated.contains(req))
  {
    return true;
  }
  // See if we can permutate the candidates for blamed
  // requirement; there may be no candidates if the resource
  // associated with the requirement is already resolved.
  if (permutation.canRemoveCandidate(req))
  {
    permutation.removeFirstCandidate(req);
    mutated.add(req);
    return true;
  }
  return false;
}

代码示例来源：origin: forge/roaster

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: org.eclipse.tycho/org.eclipse.osgi

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: apache/felix

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: biz.aQute.bnd/biz.aQute.bnd

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

public Candidates permutate(Requirement req)
{
  if (!Util.isMultiple(req) && canRemoveCandidate(req))
  {
    Candidates perm = copy();
    perm.removeFirstCandidate(req);
    return perm;
  }
  return null;
}

代码示例来源：origin: org.eclipse/osgi

private static void permutate(
  Candidates allCandidates, Requirement req, List<Candidates> permutations)
{
  if (!Util.isMultiple(req))
  {
    List<Capability> candidates = allCandidates.getCandidates(req);
    if ((candidates != null) && (candidates.size() > 1 || Util.isOptional(req)))
    {
      Candidates perm = allCandidates.copy();
      candidates = perm.getCandidates(req);
      candidates.remove(0);
      if (candidates.isEmpty())
      {
        perm.clearCandidates(req);
      }
      permutations.add(perm);
    }
  }
}

代码示例来源：origin: forge/roaster

boolean checkMultiple(
    UsedBlames usedBlames,
    Blame usedBlame,
    Candidates permutation)
{
  // Check the root requirement to see if it is a multiple cardinality
  // requirement.
  CandidateSelector candidates = null;
  Requirement req = usedBlame.m_reqs.get(0);
  if (Util.isMultiple(req))
  {
    // Create a copy of the current permutation so we can remove the
    // candidates causing the blame.
    if (m_multipleCardCandidates == null)
    {
      m_multipleCardCandidates = permutation.copy();
    }
    // Get the current candidate list and remove all the offending root
    // cause candidates from a copy of the current permutation.
    candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  }
  // We only are successful if there is at least one candidate left
  // for the requirement
  return (candidates != null) && !candidates.isEmpty();
}

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

boolean checkMultiple(
    UsedBlames usedBlames,
    Blame usedBlame,
    Candidates permutation)
{
  // Check the root requirement to see if it is a multiple cardinality
  // requirement.
  CandidateSelector candidates = null;
  Requirement req = usedBlame.m_reqs.get(0);
  if (Util.isMultiple(req))
  {
    // Create a copy of the current permutation so we can remove the
    // candidates causing the blame.
    if (m_multipleCardCandidates == null)
    {
      m_multipleCardCandidates = permutation.copy();
    }
    // Get the current candidate list and remove all the offending root
    // cause candidates from a copy of the current permutation.
    candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  }
  // We only are successful if there is at least one candidate left
  // for the requirement
  return (candidates != null) && !candidates.isEmpty();
}

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

boolean checkMultiple(
    UsedBlames usedBlames,
    Blame usedBlame,
    Candidates permutation)
{
  // Check the root requirement to see if it is a multiple cardinality
  // requirement.
  CandidateSelector candidates = null;
  Requirement req = usedBlame.m_reqs.get(0);
  if (Util.isMultiple(req))
  {
    // Create a copy of the current permutation so we can remove the
    // candidates causing the blame.
    if (m_multipleCardCandidates == null)
    {
      m_multipleCardCandidates = permutation.copy();
    }
    // Get the current candidate list and remove all the offending root
    // cause candidates from a copy of the current permutation.
    candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  }
  // We only are successful if there is at least one candidate left
  // for the requirement
  return (candidates != null) && !candidates.isEmpty();
}

代码示例来源：origin: org.eclipse.scout.sdk.deps/org.eclipse.osgi

private boolean checkMultiple(
  ResolveSession session,
  UsedBlames usedBlames,
  Blame usedBlame,
  Candidates permutation)
{
  // Check the root requirement to see if it is a multiple cardinality
  // requirement.
  List<Capability> candidates = null;
  Requirement req = usedBlame.m_reqs.get(0);
  if (Util.isMultiple(req))
  {
    // Create a copy of the current permutation so we can remove the
    // candidates causing the blame.
    if (session.getMultipleCardCandidates() == null)
    {
      session.setMultipleCardCandidates(permutation.copy());
    }
    // Get the current candidate list and remove all the offending root
    // cause candidates from a copy of the current permutation.
    candidates = session.getMultipleCardCandidates().clearCandidates(req, usedBlames.getRootCauses(req));
  }
  // We only are successful if there is at least one candidate left
  // for the requirement
  return (candidates != null) && !candidates.isEmpty();
}