本文整理了Java中org.broadinstitute.gatk.utils.Utils.longestCommonSuffix()方法的一些代码示例，展示了Utils.longestCommonSuffix()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Utils.longestCommonSuffix()方法的具体详情如下：
包路径：org.broadinstitute.gatk.utils.Utils
类名称：Utils
方法名：longestCommonSuffix

Utils.longestCommonSuffix介绍

[英]Get the length of the longest common suffix of seq1 and seq2
[中]获取seq1和seq2最长公共后缀的长度

代码示例

代码示例来源：origin: broadgsa/gatk

int reverseEdgeMatch = Utils.longestCommonSuffix(reference, alternate, Integer.MAX_VALUE);

代码示例来源：origin: broadgsa/gatk

@Test
public void testLongestCommonOps() {
  for ( int prefixLen = 0; prefixLen < 20; prefixLen++ ) {
    for ( int extraSeq1Len = 0; extraSeq1Len < 10; extraSeq1Len++ ) {
      for ( int extraSeq2Len = 0; extraSeq2Len < 10; extraSeq2Len++ ) {
        for ( int max = 0; max < 50; max++ ) {
          final String prefix = Utils.dupString("A", prefixLen);
          final int expected = Math.min(prefixLen, max);
          {
            final String seq1 = prefix + Utils.dupString("C", extraSeq1Len);
            final String seq2 = prefix + Utils.dupString("G", extraSeq1Len);
            Assert.assertEquals(Utils.longestCommonPrefix(seq1.getBytes(), seq2.getBytes(), max), expected, "LongestCommonPrefix failed: seq1 " + seq1 + " seq2 " + seq2 + " max " + max);
          }
          {
            final String seq1 = Utils.dupString("C", extraSeq1Len) + prefix;
            final String seq2 = Utils.dupString("G", extraSeq1Len) + prefix;
            Assert.assertEquals(Utils.longestCommonSuffix(seq1.getBytes(), seq2.getBytes(), max), expected, "longestCommonSuffix failed: seq1 " + seq1 + " seq2 " + seq2 + " max " + max);
          }
        }
      }
    }
  }
}