org.eclipse.xsd.XSDSimpleTypeDefinition.getEffectivePatternFacet()方法的使用及代码示例

x33g5p2x  于2022-02-03 转载在 其他  
字(1.4k)|赞(0)|评价(0)|浏览(95)

本文整理了Java中org.eclipse.xsd.XSDSimpleTypeDefinition.getEffectivePatternFacet()方法的一些代码示例,展示了XSDSimpleTypeDefinition.getEffectivePatternFacet()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。XSDSimpleTypeDefinition.getEffectivePatternFacet()方法的具体详情如下:
包路径:org.eclipse.xsd.XSDSimpleTypeDefinition
类名称:XSDSimpleTypeDefinition
方法名:getEffectivePatternFacet

XSDSimpleTypeDefinition.getEffectivePatternFacet介绍

[英]Returns the value of the 'Effective Pattern Facet' reference.

This represents the org.eclipse.xsd.XSDPatternFacet of the #getFacets. To iterate through each pattern that applies for this type, use the list returned by getEffectivePatternFacet(). XSDPatternFacet#getValue().
[中]返回“Effective Pattern Facet”引用的值。
这代表组织。日食xsd。#getFacets的XSDPatterFacet。要遍历应用于此类型的每个模式,请使用getEffectivePatternFacet()返回的列表。XSDPatternFacet#getValue()。

代码示例

代码示例来源:origin: org.eclipse/org.eclipse.xsd

if (patternFacets.isEmpty())
 XSDPatternFacet basePatternFacet = theBaseTypeDefinition.getEffectivePatternFacet();
 if (basePatternFacet != null)
 XSDPatternFacet effectiveBasePatternFacet = theBaseTypeDefinition.getEffectivePatternFacet();
 if (effectiveBasePatternFacet != null)

代码示例来源:origin: org.eclipse.xsd/org.eclipse.xsd

if (patternFacets.isEmpty())
 XSDPatternFacet basePatternFacet = theBaseTypeDefinition.getEffectivePatternFacet();
 if (basePatternFacet != null)
 XSDPatternFacet effectiveBasePatternFacet = theBaseTypeDefinition.getEffectivePatternFacet();
 if (effectiveBasePatternFacet != null)

相关文章

微信公众号

最新文章

更多

XSDSimpleTypeDefinition类方法