本文整理了Java中com.ait.lienzo.client.core.shape.Attributes.getStarPoints()
方法的一些代码示例,展示了Attributes.getStarPoints()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Attributes.getStarPoints()
方法的具体详情如下:
包路径:com.ait.lienzo.client.core.shape.Attributes
类名称:Attributes
方法名:getStarPoints
暂无
代码示例来源:origin: ahome-it/lienzo-core
/**
* Returns the number of Stars points.
*
* @return int
*/
public int getStarPoints()
{
return getAttributes().getStarPoints();
}
代码示例来源:origin: org.dashbuilder/dashbuilder-lienzo-core
/**
* Returns the number of Stars points.
*
* @return int
*/
public int getStarPoints()
{
return getAttributes().getStarPoints();
}
代码示例来源:origin: com.ahome-it/lienzo-core
/**
* Returns the number of Stars points.
*
* @return int
*/
public int getStarPoints()
{
return getAttributes().getStarPoints();
}
代码示例来源:origin: ahome-it/lienzo-core
/**
* Returns the number of Stars points.
*
* @return int
*/
public int getStarPoints()
{
return getAttributes().getStarPoints();
}
代码示例来源:origin: org.dashbuilder/dashbuilder-lienzo-core
/**
* Draws this star.
*
* @param context
*/
@Override
protected boolean prepare(final Context2D context, final Attributes attr, final double alpha)
{
final int s = attr.getStarPoints();
final double ir = attr.getInnerRadius();
final double or = attr.getOuterRadius();
if ((s > 4) && (ir > 0) && (or > 0) && (or > ir))
{
context.beginPath();
context.moveTo(0, 0 - or);
for (int n = 1; n < s * 2; n++)
{
double radius = n % 2 == 0 ? or : ir;
context.lineTo(radius * Math.sin(n * Math.PI / s), -1 * radius * Math.cos(n * Math.PI / s));
}
context.closePath();
return true;
}
return false;
}
代码示例来源:origin: com.ahome-it/lienzo-core
private boolean parse(final Attributes attr)
final int sp = attr.getStarPoints();
代码示例来源:origin: ahome-it/lienzo-core
private boolean parse(final Attributes attr)
final int sp = attr.getStarPoints();
代码示例来源:origin: ahome-it/lienzo-core
private boolean parse(final Attributes attr)
final int sp = attr.getStarPoints();
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