本文整理了Java中cyclops.reactive.ReactiveSeq.combine方法的一些代码示例，展示了ReactiveSeq.combine的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。ReactiveSeq.combine方法的具体详情如下：
包路径：cyclops.reactive.ReactiveSeq
类名称：ReactiveSeq
方法名：combine

ReactiveSeq.combine介绍

暂无

代码示例

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(Spouts.of(1,1,2,3)
        .combine((a, b)->a.equals(b),Semigroups.intSum)
        .toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(of(1,1,2,3)
      .combine((a, b)->a.equals(b),Semigroups.intSum)
      .toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combineNoOrderMonoid(){
  assertThat(of(1,2,3)
      .combine(Monoids.intSum,(a, b)->a.equals(b))
      .toList(),equalTo(Arrays.asList(1,2,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void testCombineMonoidTwo(){
  assertThat(of(1,1,2,3)
          .combine((a, b)->a.equals(b),Monoids.intMult)
          .findFirst().get()
      , equalTo(1));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(ReactiveSeq.of(1,1,2,3)
        .combine((a, b)->a.equals(b),Semigroups.intSum)
        .toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(of(1,1,2,3)
        .combine((a, b)->a.equals(b),Semigroups.intSum)
        .toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void testCombineMonoid(){
  assertThat(of(1,1,2,3)
      .combine(Monoids.intMult,(a, b)->a.equals(b))
      .findFirst().get()
      , equalTo(1));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combineNoOrder(){
  assertThat(of(1,2,3)
      .combine((a, b)->a.equals(b), Semigroups.intSum)
      .toList(),equalTo(Arrays.asList(1,2,3)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(of(1,1,2,3)
        .combine((a, b)->a.equals(b),Semigroups.intSum)
        .toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combineTerminate() {
  assertThat(of(1, 2, 3, 4, 5, 6, 7, 8)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .findFirst(), Matchers.equalTo(Optional.of(6)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combine(){
  assertThat(Spouts.of(1,1,2,3)
        .combine((a, b)->a.equals(b),Semigroups.intSum)
        .to(Streamable::fromStream).toList(),equalTo(Arrays.asList(4,3)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combineOneFirstOrError() {
  assertThat(ofWait(1)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .findFirstOrError(), Matchers.equalTo(LazyEither.right(1)));
}
@Test

代码示例来源：origin: aol/cyclops

@Test
public void combineOne() {
  assertThat(ofWait(1)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.of(1)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combine() {
  assertThat(of(1, 2, 3, 4, 5, 6, 7, 8)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.of(6)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combineEmpty() {
  assertThat(this.<Integer>of()
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.nothing()));
}

代码示例来源：origin: aol/cyclops

@Test
public void combine() {
  assertThat(ofWait(1, 2, 3, 4, 5, 6, 7, 8).combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.of(6)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combineOneFirstOrError() {
  assertThat(of(1)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .findFirstOrError(), Matchers.equalTo(LazyEither.right(1)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combineOne() {
  assertThat(of(1)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.of(1)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combineTwo() {
    assertThat(ofWait(1, 2)
        .combine((a, b) -> a < 5, Semigroups.intSum)
        .takeOne(), Matchers.equalTo(Maybe.of(3)));
}

代码示例来源：origin: aol/cyclops

@Test
public void combineTwo() {
  assertThat(of(1, 2)
      .combine((a, b) -> a < 5, Semigroups.intSum)
      .takeOne(), Matchers.equalTo(Maybe.of(3)));
}