本文整理了Java中cyclops.reactive.ReactiveSeq.foldParallel方法的一些代码示例，展示了ReactiveSeq.foldParallel的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。ReactiveSeq.foldParallel方法的具体详情如下：
包路径：cyclops.reactive.ReactiveSeq
类名称：ReactiveSeq
方法名：foldParallel

ReactiveSeq.foldParallel介绍

暂无

代码示例

代码示例来源：origin: aol/cyclops

default <R> R foldParallel(ForkJoinPool fj,Function<? super Stream<T>,? extends R> fn){
  return fj.submit(() -> foldParallel(fn)).join();
}

代码示例来源：origin: aol/cyclops

.build();
ReactiveSeq<Iterator<? extends R>> stream = ReactiveSeq.<Stream<? extends R>>generate(() -> foldParallel(fn))
                              .take(1)
                              .map(s->s.iterator());

代码示例来源：origin: aol/cyclops

.build();
ReactiveSeq<? extends Iterator<? extends R>> stream = ReactiveSeq.<Stream<? extends R>>generate(() -> foldParallel(fj,fn))
    .take(1)
    .map(s->s.iterator());

代码示例来源：origin: com.oath.cyclops/cyclops

default <R> R foldParallel(ForkJoinPool fj,Function<? super Stream<T>,? extends R> fn){
  return fj.submit(() -> foldParallel(fn)).join();
}

代码示例来源：origin: com.oath.cyclops/cyclops

.build();
ReactiveSeq<? extends Iterator<? extends R>> stream = ReactiveSeq.<Stream<? extends R>>generate(() -> foldParallel(fj,fn))
    .take(1)
    .map(s->s.iterator());

代码示例来源：origin: com.oath.cyclops/cyclops

.build();
ReactiveSeq<Iterator<? extends R>> stream = ReactiveSeq.<Stream<? extends R>>generate(() -> foldParallel(fn))
                              .take(1)
                              .map(s->s.iterator());