本文整理了Java中com.badlogic.gdx.math.Rectangle.overlaps方法的一些代码示例，展示了Rectangle.overlaps的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Rectangle.overlaps方法的具体详情如下：
包路径：com.badlogic.gdx.math.Rectangle
类名称：Rectangle
方法名：overlaps

Rectangle.overlaps介绍

暂无

代码示例

代码示例来源：origin: libgdx/libgdx

public static boolean overlaps (Rectangle r1, Rectangle r2) {
  return r1.overlaps(r2);
}

代码示例来源：origin: libgdx/libgdx

public static boolean overlaps (Rectangle r1, Rectangle r2) {
  return r1.overlaps(r2);
}

代码示例来源：origin: libgdx/libgdx

/** Determines whether the given rectangles intersect and, if they do, sets the supplied {@code intersection} rectangle to the
 * area of overlap.
 * @return Whether the rectangles intersect */
static public boolean intersectRectangles (Rectangle rectangle1, Rectangle rectangle2, Rectangle intersection) {
  if (rectangle1.overlaps(rectangle2)) {
    intersection.x = Math.max(rectangle1.x, rectangle2.x);
    intersection.width = Math.min(rectangle1.x + rectangle1.width, rectangle2.x + rectangle2.width) - intersection.x;
    intersection.y = Math.max(rectangle1.y, rectangle2.y);
    intersection.height = Math.min(rectangle1.y + rectangle1.height, rectangle2.y + rectangle2.height) - intersection.y;
    return true;
  }
  return false;
}

代码示例来源：origin: libgdx/libgdx

/** Determines whether the given rectangles intersect and, if they do, sets the supplied {@code intersection} rectangle to the
 * area of overlap.
 * @return Whether the rectangles intersect */
static public boolean intersectRectangles (Rectangle rectangle1, Rectangle rectangle2, Rectangle intersection) {
  if (rectangle1.overlaps(rectangle2)) {
    intersection.x = Math.max(rectangle1.x, rectangle2.x);
    intersection.width = Math.min(rectangle1.x + rectangle1.width, rectangle2.x + rectangle2.width) - intersection.x;
    intersection.y = Math.max(rectangle1.y, rectangle2.y);
    intersection.height = Math.min(rectangle1.y + rectangle1.height, rectangle2.y + rectangle2.height) - intersection.y;
    return true;
  }
  return false;
}

代码示例来源：origin: libgdx/libgdx

@Test
  public void testRectangle () {
    Rectangle r1 = new Rectangle(0, 0, 1, 1);
    Rectangle r2 = new Rectangle(1, 0, 2, 1);
    assertTrue(r1.overlaps(r1));
    assertFalse(r1.overlaps(r2));
    assertTrue(r1.contains(0, 0));
  }
}

代码示例来源：origin: libgdx/libgdx

private boolean isCulled () {
    // we start by setting the stage coordinates to this
    // actors coordinates which are relative to its parent
    // Group.
    float stageX = getX();
    float stageY = getY();
    // now we go up the hierarchy and add all the parents'
    // coordinates to this actors coordinates. Note that
    // this assumes that neither this actor nor any of its
    // parents are rotated or scaled!
    Actor parent = this.getParent();
    while (parent != null) {
      stageX += parent.getX();
      stageY += parent.getY();
      parent = parent.getParent();
    }
    // now we check if the rectangle of this actor in screen
    // coordinates is in the rectangle spanned by the camera's
    // view. This assumes that the camera has no zoom and is
    // not rotated!
    actorRect.set(stageX, stageY, getWidth(), getHeight());
    camRect.set(camera.position.x - camera.viewportWidth / 2.0f, camera.position.y - camera.viewportHeight / 2.0f,
      camera.viewportWidth, camera.viewportHeight);
    visible = camRect.overlaps(actorRect);
    return !visible;
  }
}

代码示例来源：origin: libgdx/libgdx

koalaRect.x += koala.velocity.x;
for (Rectangle tile : tiles) {
  if (koalaRect.overlaps(tile)) {
    koala.velocity.x = 0;
    break;
koalaRect.y += koala.velocity.y;
for (Rectangle tile : tiles) {
  if (koalaRect.overlaps(tile)) {

代码示例来源：origin: libgdx/libgdx

if (viewBounds.contains(imageBounds) || viewBounds.overlaps(imageBounds)) {
  final float u1 = region.getU();
  final float v1 = region.getV2();

代码示例来源：origin: libgdx/libgdx

if (viewBounds.contains(imageBounds) || viewBounds.overlaps(imageBounds)) {
  final float u1 = region.getU();
  final float v1 = region.getV2();

代码示例来源：origin: stackoverflow.com

while(iter2.hasNext()) {
 Rectangle bullet = iter2.next();
 bullet.x -= 200 * Gdx.graphics.getDeltaTime();
 if(bullet.x + 48 < 0) iter2.remove();
 iter = meteorites.iterator();
 while(iter.hasNext()) {
  if(bullet.overlaps(iter.next())) {
   iter2.remove();
   iter.remove();
  }
 }
}

代码示例来源：origin: stackoverflow.com

for (Rectangle spacebarRectangle : spacebar.getSpacebarRectangles()) {   // section of code
    if (spacebarRectangle.overlaps(dino.getDinoRectangle())) {
      spacebarSound.play();
      break;
    }
}

代码示例来源：origin: stackoverflow.com

dino.setOverlapping(false);
for (Rectangle spacebarRectangle : spacebar.getSpacebarRectangles()) {   // section of code
    if (!dino.isOverlapping() && spacebarRectangle.overlaps(dino.getDinoRectangle())) {
      dino.setOverlapping(true);
      spacebarSound.play();
    }
}

代码示例来源：origin: com.badlogicgames.gdx/gdx

public static boolean overlaps (Rectangle r1, Rectangle r2) {
  return r1.overlaps(r2);
}

代码示例来源：origin: stackoverflow.com

if(Gdx.input.isKeyPressed(Keys.D){
  float requestedX, requestedY;
  //calculate the requested coordinates
  Rectangle newPlayerPositionRectangle = new Rectangle(requestedX, requestedY, player.getWidth(), player.getHeight());
  if (newPlayerPositionRectangle.overlaps(map) {
    //move the player
  } else {
    //move the player only to the edge of the map and stop there
  }
}

代码示例来源：origin: com.badlogicgames.gdx/gdx

/** Determines whether the given rectangles intersect and, if they do, sets the supplied {@code intersection} rectangle to the
 * area of overlap.
 * @return Whether the rectangles intersect */
static public boolean intersectRectangles (Rectangle rectangle1, Rectangle rectangle2, Rectangle intersection) {
  if (rectangle1.overlaps(rectangle2)) {
    intersection.x = Math.max(rectangle1.x, rectangle2.x);
    intersection.width = Math.min(rectangle1.x + rectangle1.width, rectangle2.x + rectangle2.width) - intersection.x;
    intersection.y = Math.max(rectangle1.y, rectangle2.y);
    intersection.height = Math.min(rectangle1.y + rectangle1.height, rectangle2.y + rectangle2.height) - intersection.y;
    return true;
  }
  return false;
}

代码示例来源：origin: libgdx/box2dlights

protected boolean cull() {
  if (!rayHandler.culling) {
    culled = false;
  } else {
    updateBoundingRects();
    culled = chainLightBounds.width > 0 &&
         chainLightBounds.height > 0 &&
         !chainLightBounds.overlaps(rayHandlerBounds);
  }
  return culled;
}

代码示例来源：origin: com.badlogicgames.box2dlights/box2dlights

protected boolean cull() {
  if (!rayHandler.culling) {
    culled = false;
  } else {
    updateBoundingRects();
    culled = chainLightBounds.width > 0 &&
         chainLightBounds.height > 0 &&
         !chainLightBounds.overlaps(rayHandlerBounds);
  }
  return culled;
}

代码示例来源：origin: stackoverflow.com

public static boolean intersect(Rectangle r1, Rectangle r2, Rectangle intersection) {
  if (!r1.overlaps(r2)) {
    return false;
  }

  float x = Math.max(r1.x, r2.x);
  float y = Math.max(r1.y, r2.y);
  float width = Math.min(r1.x + r1.width, r2.x + r2.width) - x;
  float height = Math.min(r1.y + r1.height, r2.y + r2.height) - y;
  intersection.set(x, y, width, height);

  return true;
}

代码示例来源：origin: jmrapp1/SpaceInvaders

public void handleCollision(WorldObject wo) {
  collisionTestRect.set(desired.x, desired.y, width, height);
  if (wo.getBounds().overlaps(collisionTestRect)) {
    if (onCollide(wo)) {
      resetLastMove();
    } else if (wo instanceof AbstractEntity) {
      AbstractEntity ent = (AbstractEntity) wo;
      if (ent.onCollide(this)) {
        ent.resetLastMove();
      }
    }
  }
}

代码示例来源：origin: Var3D/var3dframe

/**
 * r1是否在r2内
 */
public boolean isOverlaps(Actor r1, Actor r2) {
  rect1.set(r1.getX(), r1.getY(), r1.getWidth(), r1.getHeight());
  rect2.set(r2.getX(), r2.getY(), r2.getWidth(), r2.getHeight());
  return rect1.overlaps(rect2);
}