本文整理了Java中opennlp.tools.util.Span.compareTo()方法的一些代码示例，展示了Span.compareTo()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Span.compareTo()方法的具体详情如下：
包路径：opennlp.tools.util.Span
类名称：Span
方法名：compareTo

Span.compareTo介绍

[英]Compares the specified span to the current span.
[中]将指定范围与当前范围进行比较。

代码示例

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToLower() {
 Span a = new Span(100, 1000);
 Span b = new Span(10, 50);
 Assert.assertEquals(true, a.compareTo(b) > 0);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEqualsDiffType2() {
 Span a = new Span(30, 1000, "b");
 Span b = new Span(30, 1000, "a");
 Assert.assertEquals(true, a.compareTo(b) == 1);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEqualsNullType2() {
 Span a = new Span(30, 1000, "b");
 Span b = new Span(30, 1000);
 Assert.assertEquals(true, a.compareTo(b) == -1);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEquals() {
 Span a = new Span(30, 1000);
 Span b = new Span(30, 1000);
 Assert.assertEquals(true, a.compareTo(b) == 0);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEqualsSameType() {
 Span a = new Span(30, 1000, "a");
 Span b = new Span(30, 1000, "a");
 Assert.assertEquals(true, a.compareTo(b) == 0);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEqualsDiffType1() {
 Span a = new Span(30, 1000, "a");
 Span b = new Span(30, 1000, "b");
 Assert.assertEquals(true, a.compareTo(b) == -1);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToEqualsNullType1() {
 Span a = new Span(30, 1000);
 Span b = new Span(30, 1000, "b");
 Assert.assertEquals(true, a.compareTo(b) == 1);
}

代码示例来源：origin: apache/opennlp

/**
 * Test for {@link Span#compareTo(Object)}.
 */
@Test
public void testCompareToHigher() {
 Span a = new Span(100, 200);
 Span b = new Span(300, 400);
 Assert.assertEquals(true, a.compareTo(b) < 0);
}

代码示例来源：origin: apache/opennlp-sandbox

public int compareTo(Mention e) {
 return span.compareTo(e.span);
}

代码示例来源：origin: Ailab403/ailab-mltk4j

public int compareTo(Mention e) {
 return span.compareTo(e.span);
}

代码示例来源：origin: spinscale/elasticsearch-opennlp-plugin

public int compareTo(TextAnnotation a) {
  int c = span.compareTo(a.span);
  if (c == 0) {
    c = Double.compare(prob, a.prob);
    if (c == 0) {
      c = type.compareTo(a.type);
    }
  }
  return c;
}

代码示例来源：origin: org.cogroo.lang.pt_br/cogroo-addon-pt_br

public int compareTo(Omission o) {
  return span.compareTo(o.getSpan());
}

代码示例来源：origin: cogroo/cogroo4

public int compareTo(Omission o) {
  return span.compareTo(o.getSpan());
}

代码示例来源：origin: org.cogroo/cogroo-gc

public int compare(Mistake m1, Mistake m2) {
 // First we check if they overlap. If they don't we simply use the start position
 Span a = new Span(m1.getStart(), m1.getEnd());
 Span b = new Span(m2.getStart(), m2.getEnd());
 if(!a.intersects(b)) {
  return a.compareTo(b);
 }
 
 // they intersect, so we should sort using the priority. The higher the
 // number, the higher th priority
 if(m1.getRulePriority() > m2.getRulePriority()) {
  return -1;
 } else if(m1.getRulePriority() < m2.getRulePriority()) {
  return 1;
 } else {
  // equal priority! so we try to use the rule id
  if(m2.getRuleIdentifier().startsWith("xml:")) {
   Integer id1 = new Integer(m1.getRuleIdentifier().substring(4));
   Integer id2 = new Integer(m2.getRuleIdentifier().substring(4));
   
   return id1.compareTo(id2);
  }
  return m1.getRuleIdentifier().compareTo(m2.getRuleIdentifier());
 }
}

代码示例来源：origin: cogroo/cogroo4

public int compare(Mistake m1, Mistake m2) {
 // First we check if they overlap. If they don't we simply use the start position
 Span a = new Span(m1.getStart(), m1.getEnd());
 Span b = new Span(m2.getStart(), m2.getEnd());
 if(!a.intersects(b)) {
  return a.compareTo(b);
 }
 
 // they intersect, so we should sort using the priority. The higher the
 // number, the higher th priority
 if(m1.getRulePriority() > m2.getRulePriority()) {
  return -1;
 } else if(m1.getRulePriority() < m2.getRulePriority()) {
  return 1;
 } else {
  // equal priority! so we try to use the rule id
  if(m2.getRuleIdentifier().startsWith("xml:")) {
   Integer id1 = new Integer(m1.getRuleIdentifier().substring(4));
   Integer id2 = new Integer(m2.getRuleIdentifier().substring(4));
   
   return id1.compareTo(id2);
  }
  return m1.getRuleIdentifier().compareTo(m2.getRuleIdentifier());
 }
}

代码示例来源：origin: Ailab403/ailab-mltk4j

public int compareTo(opennlp.tools.coref.mention.Parse p) {
 if (p == this) {
  return 0;
 }
 if (getSentenceNumber() < p.getSentenceNumber()) {
  return -1;
 }
 else if (getSentenceNumber() > p.getSentenceNumber()) {
  return 1;
 }
 else {
  
  if (parse.getSpan().getStart() == p.getSpan().getStart() &&
    parse.getSpan().getEnd() == p.getSpan().getEnd()) {
   System.out.println("Maybe incorrect measurement!");
   
   Stack<Parse> parents = new Stack<Parse>();
   
   
   
   
   // get parent and update distance
   // if match return distance
   // if not match do it again
   }
  
  return parse.getSpan().compareTo(p.getSpan());
 }
}

代码示例来源：origin: apache/opennlp-sandbox

public int compareTo(opennlp.tools.coref.mention.Parse p) {
 if (p == this) {
  return 0;
 }
 if (getSentenceNumber() < p.getSentenceNumber()) {
  return -1;
 }
 else if (getSentenceNumber() > p.getSentenceNumber()) {
  return 1;
 }
 else {
  
  if (parse.getSpan().getStart() == p.getSpan().getStart() &&
    parse.getSpan().getEnd() == p.getSpan().getEnd()) {
   System.out.println("Maybe incorrect measurement!");
   
   Stack<Parse> parents = new Stack<Parse>();
   
   
   
   
   // get parent and update distance
   // if match return distance
   // if not match do it again
  }
  
  return parse.getSpan().compareTo(p.getSpan());
 }
}