本文整理了Java中android.view.View.getLabelFor()
方法的一些代码示例,展示了View.getLabelFor()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。View.getLabelFor()
方法的具体详情如下:
包路径:android.view.View
类名称:View
方法名:getLabelFor
暂无
代码示例来源:origin: square/assertj-android
@TargetApi(JELLY_BEAN_MR1)
public S hasLabelFor(int id) {
isNotNull();
int actualId = actual.getLabelFor();
assertThat(actualId) //
.overridingErrorMessage("Expected to have label for ID <%s> but was <%s>", id, actualId) //
.isEqualTo(id);
return myself;
}
代码示例来源:origin: kingargyle/adt-leanback-support
public static int getLabelFor(View view) {
return view.getLabelFor();
}
代码示例来源:origin: com.squareup.assertj/assertj-android
@TargetApi(JELLY_BEAN_MR1)
public S hasLabelFor(int id) {
isNotNull();
int actualId = actual.getLabelFor();
assertThat(actualId) //
.overridingErrorMessage("Expected to have label for ID <%s> but was <%s>", id, actualId) //
.isEqualTo(id);
return myself;
}
代码示例来源:origin: com.google.android.apps.common.testing.accessibility.framework/accessibility-test-framework
private static View lookForLabelForViewInViewAndChildren(View view, View childToSkip,
int idToFind) {
if (view.getLabelFor() == idToFind) {
return view;
}
if (!(view instanceof ViewGroup)) {
return null;
}
ViewGroup viewGroup = (ViewGroup) view;
for (int i = 0; i < viewGroup.getChildCount(); ++i) {
View child = viewGroup.getChildAt(i);
if (!child.equals(childToSkip)) {
View labelingView = lookForLabelForViewInViewAndChildren(child, null, idToFind);
if (labelingView != null) {
return labelingView;
}
}
}
return null;
}
代码示例来源:origin: jbruchanov/AnUitor
data.put("LabelFor", IdsHelper.getNameForId(v.getLabelFor()));
data.put("LayerDirection", translator.layoutDirection(v.getLayoutDirection()));
data.put("Display:", String.valueOf(v.getDisplay()));
内容来源于网络,如有侵权,请联系作者删除!